パンダで指定された時間間隔で1時間ごとのデータ範囲を生成

Question

Pandasを使用して、定義済みの日付の間に1時間ごとの間隔のセットを生成しようとしています。私が使用している：

import pandas as pd 

print pd.date_range(start='2013-04-01', end='2013-04-30', freq='1H') 

DatetimeIndex(['2013-04-01 00:00:00', '2013-04-01 01:00:00', 
       '2013-04-01 02:00:00', '2013-04-01 03:00:00', 
       '2013-04-01 04:00:00', '2013-04-01 05:00:00', 
       '2013-04-01 06:00:00', '2013-04-01 07:00:00', 
       '2013-04-01 08:00:00', '2013-04-01 09:00:00', 
       ... 
       '2013-04-29 15:00:00', '2013-04-29 16:00:00', 
       '2013-04-29 17:00:00', '2013-04-29 18:00:00', 
       '2013-04-29 19:00:00', '2013-04-29 20:00:00', 
       '2013-04-29 21:00:00', '2013-04-29 22:00:00', 
       '2013-04-29 23:00:00', '2013-04-30 00:00:00'], 
       dtype='datetime64[ns]', length=697, freq='H') 

しかし、それはすなわち、[0-1]、[2-3]、[4-5]は、...しかし、私は何が必要、他の全ての時間間隔を生成し、 [0-1]、[1-2]、[2-3]のようなパーティションです...どうすればいいですか？前もって感謝します。

所望の出力：

DatetimeIndex(['2013-04-01 00:00:00', '2013-04-01 01:00:00', 
       '2013-04-01 01:00:00', '2013-04-01 02:00:00', 
       '2013-04-01 02:00:00', '2013-04-01 03:00:00', 
       '2013-04-01 03:00:00', '2013-04-01 04:00:00', 
       '2013-04-01 04:00:00', '2013-04-01 05:00:00', 
       ... 
       '2013-04-29 19:00:00', '2013-04-29 20:00:00', 
       '2013-04-29 20:00:00', '2013-04-29 21:00:00', 
       '2013-04-29 21:00:00', '2013-04-29 22:00:00', 
       '2013-04-29 22:00:00', '2013-04-29 23:00:00', 
       '2013-04-29 23:00:00', '2013-04-30 00:00:00'], 
       dtype='datetime64[ns]', length=697, freq='H') 

Answer 1

ここだ片道

In [2249]: d = pd.date_range(start='2013-04-01', end='2013-04-30', freq='H') 

In [2250]: pd.DatetimeIndex([v for p in zip(d, d[1:]) for v in p]) 
Out[2250]: 
DatetimeIndex(['2013-04-01 00:00:00', '2013-04-01 01:00:00', 
       '2013-04-01 01:00:00', '2013-04-01 02:00:00', 
       '2013-04-01 02:00:00', '2013-04-01 03:00:00', 
       '2013-04-01 03:00:00', '2013-04-01 04:00:00', 
       '2013-04-01 04:00:00', '2013-04-01 05:00:00', 
       ... 
       '2013-04-29 19:00:00', '2013-04-29 20:00:00', 
       '2013-04-29 20:00:00', '2013-04-29 21:00:00', 
       '2013-04-29 21:00:00', '2013-04-29 22:00:00', 
       '2013-04-29 22:00:00', '2013-04-29 23:00:00', 
       '2013-04-29 23:00:00', '2013-04-30 00:00:00'], 
       dtype='datetime64[ns]', length=1392, freq=None) 

あるいは、

In [2252]: pd.DatetimeIndex(itertools.chain(*zip(d, d[1:]))) 
Out[2252]: 
DatetimeIndex(['2013-04-01 00:00:00', '2013-04-01 01:00:00', 
       '2013-04-01 01:00:00', '2013-04-01 02:00:00', 
       '2013-04-01 02:00:00', '2013-04-01 03:00:00', 
       '2013-04-01 03:00:00', '2013-04-01 04:00:00', 
       '2013-04-01 04:00:00', '2013-04-01 05:00:00', 
       ... 
       '2013-04-29 19:00:00', '2013-04-29 20:00:00', 
       '2013-04-29 20:00:00', '2013-04-29 21:00:00', 
       '2013-04-29 21:00:00', '2013-04-29 22:00:00', 
       '2013-04-29 22:00:00', '2013-04-29 23:00:00', 
       '2013-04-29 23:00:00', '2013-04-30 00:00:00'], 
       dtype='datetime64[ns]', length=1392, freq=None) 

Answer 2

ワンライナーは、直接それをやって：

In [237]: pd.date_range(start='2013-04-01', end='2013-04-30', freq='0.5H1U').round('1H') 
Out[237]: 
DatetimeIndex(['2013-04-01 00:00:00', '2013-04-01 01:00:00', 
       '2013-04-01 01:00:00', '2013-04-01 02:00:00', 
       '2013-04-01 02:00:00', '2013-04-01 03:00:00', 
       '2013-04-01 03:00:00', '2013-04-01 04:00:00', 
       '2013-04-01 04:00:00', '2013-04-01 05:00:00', 
       ... 
       '2013-04-29 19:00:00', '2013-04-29 20:00:00', 
       '2013-04-29 20:00:00', '2013-04-29 21:00:00', 
       '2013-04-29 21:00:00', '2013-04-29 22:00:00', 
       '2013-04-29 22:00:00', '2013-04-29 23:00:00', 
       '2013-04-29 23:00:00', '2013-04-30 00:00:00'], 
       dtype='datetime64[ns]', length=1392, freq=None) 

私は30分の1に1ミリ秒の頻度を使用しているので、丸めは常に「右側」になります。