投稿IDと表示レコードを

Question

みんなのタグマッチングを取得するにはどうすれば持って、次の表

1. 投稿
2. タグ
3. post_tags

私はポスト、タグからpostIDとtagsIDを保存post_tagテーブルのテーブルをpost_id、tag_id

ここで私のpost.phpページbu t一致するタグを取得するためにクエリを実行するにはどうすればよいですか？ここ

$stmt = $db->query('SELECT * FROM posts WHERE postID LIKE "%'.$id.'%"');     
       $stmt->execute(); 
       while($rw = $stmt->fetch()){ 

} 

私は私の実際のデータ構造を共有し、データが各テーブルに保存されているか、これはあなたのJOINテーブルで私を助けるためにアイデアを与えることを願っていますか？

これらは3つのテーブル

-- 
-- Table structure for table `blog_posts` 
-- 

CREATE TABLE IF NOT EXISTS `blog_posts` (
    `postID` int(11) unsigned NOT NULL AUTO_INCREMENT, 
    `posterID` int(11) NOT NULL, 
    `catID` int(11) NOT NULL, 
    `postTitle` varchar(90) DEFAULT NULL, 
    `postImg` varchar(255) DEFAULT NULL, 
    `postYoutube` varchar(100) DEFAULT NULL, 
    `postSlug` varchar(255) DEFAULT NULL, 
    `postDesc` text, 
    `postCont` text, 
    `postViews` int(11) NOT NULL DEFAULT '0', 
    `postDate` datetime DEFAULT NULL, 
    PRIMARY KEY (`postID`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ; 

-- 
-- Dumping data for table `blog_posts` 
-- 

INSERT INTO `blog_posts` (`postID`, `posterID`, `catID`, `postTitle`, `postImg`, `postYoutube`, `postSlug`, `postDesc`, `postCont`, `postViews`, `postDate`) VALUES 
(1, 1, 1, ' Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.', ' Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.jpg', '', '1/lorem-ipsum-giving', '<p> Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.</p>', '<p> Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.</p>', 1, '2017-08-10 11:46:36'), 
(2, 1, 3, ' Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.', ' Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.jpg', '', '2/lorem-ipsum-giving', '<p>Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.</p>', '<p>Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.</p>', 0, '2017-08-10 13:38:57'), 
(3, 1, 2, 'Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.', 'Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.jpg', '', '3/moong-dal-halwa', '<p>Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.</p>', '<p>Lorem Ipsum, giving information on its origins, as well as a random Lipsum generator.</p>', 0, '2017-08-10 13:39:40')); 

-- -------------------------------------------------------- 

-- 
-- Table structure for table `blog_posts_tags` 
-- 

CREATE TABLE IF NOT EXISTS `blog_posts_tags` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `post_id` int(11) NOT NULL, 
    `tag_id` int(11) NOT NULL, 
    PRIMARY KEY (`id`), 
    UNIQUE KEY `blog_posts_tags` (`post_id`,`tag_id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=31 ; 

-- 
-- Dumping data for table `blog_posts_tags` 
-- 

INSERT INTO `blog_posts_tags` (`id`, `post_id`, `tag_id`) VALUES 
(1, 1, 2), 
(7, 1, 4), 
(9, 1, 3), 
(2, 1, 3), 
(10, 1, 2), 
(8, 1, 5), 
(4, 1, 5), 
(24, 2, 2), 
(25, 3, 5), 
(26, 3, 1)); 

-- -------------------------------------------------------- 

-- 
-- Table structure for table `blog_tags` 
-- 

CREATE TABLE IF NOT EXISTS `blog_tags` (
    `tagID` int(11) NOT NULL AUTO_INCREMENT, 
    `tagName` varchar(32) NOT NULL, 
    `tagUrl` varchar(32) NOT NULL, 
    PRIMARY KEY (`tagID`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=61 ; 

-- 
-- Dumping data for table `blog_tags` 
-- 

INSERT INTO `blog_tags` (`tagID`, `tagName`, `tagUrl`) VALUES 
(1, 'American Food', 'american-food'), 
(2, 'Bakeries', 'bakeries'), 
(3, 'Bars', 'bars'), 
(4, 'Beef', 'beef'), 
(5, 'Cafe', 'cafe'); 

任意のヘルプですか？あなたはJOINを使用する必要が

Answer 1

、例えば：

SELECT * 
FROM blog_posts bp JOIN blog_posts_tags bpt ON bp.postID = bpt.post_id 
JOIN blog_tags bt ON bt.tagID = bpt.tag_id 
WHERE bt.tagName = 'Bakeries'; 

あなたはidで検索したい場合は、t.idWHEREで条件を使用することができ、例えば：ここで

SELECT * 
FROM blog_posts bp JOIN blog_posts_tags bpt ON bp.postID = bpt.post_id 
JOIN blog_tags bt ON bt.tagID = bpt.tag_id 
WHERE bt.tagID = 2; 

、idはIDに対応（それぞれの表内）、post_idおよびtag_idは、post_tags表内の対応する外部キー列の名前です。

ここにはSQL Fiddleです。