リストのリストから2次元リストを返すPython関数

Question

pythonの質問はこちら。リストのリストから2次元のリストを返す関数を作りたいと思います。私はitertoolsでこの機能を見つけることができませんでした。 AB用

Possibe入力=リストAAまたはAB以下に示すように（異なる長さ）

aa = [[230, 115, 90, 264], [12, 9, 5], [-1], ['on', 'off']] 
ab = [[230, 115, 90, 264], ['on', 'off']] 

出力がなければならない：AA用

[[230, 'on'], 
[230, 'off'], 
[115, 'on'], 
[115, 'off'], 
[90, 'on'], 
[90, 'off'], 
[264, 'on'], 
[264, 'off']] 

出力は次のようになります

[[230, 12, -1, 'on'], 
[230, 12, -1, 'off'], 
[230, 9, -1, 'on'], 
[230, 9, -1, 'off'], 
.... 
[264, 5, -1, 'off']] 

Answer 1

あなたが求めているのは、いくつかのイテラブルのcartesian productです：

import itertools 
import pprint 

aa = [[230, 115, 90, 264], [12, 9, 5], [-1], ['on', 'off']] 
ab = [[230, 115, 90, 264], ['on', 'off']] 

for iterable in [aa, ab]: 
    pprint.pprint(list(itertools.product(*aa))) 

結果：

[(230, 12, -1, 'on'), 
(230, 12, -1, 'off'), 
(230, 9, -1, 'on'), 
(230, 9, -1, 'off'), 
(230, 5, -1, 'on'), 
(230, 5, -1, 'off'), 
(115, 12, -1, 'on'), 
(115, 12, -1, 'off'), 
(115, 9, -1, 'on'), 
(115, 9, -1, 'off'), 
(115, 5, -1, 'on'), 
(115, 5, -1, 'off'), 
(90, 12, -1, 'on'), 
(90, 12, -1, 'off'), 
(90, 9, -1, 'on'), 
(90, 9, -1, 'off'), 
(90, 5, -1, 'on'), 
(90, 5, -1, 'off'), 
(264, 12, -1, 'on'), 
(264, 12, -1, 'off'), 
(264, 9, -1, 'on'), 
(264, 9, -1, 'off'), 
(264, 5, -1, 'on'), 
(264, 5, -1, 'off')] 
[(230, 12, -1, 'on'), 
(230, 12, -1, 'off'), 
(230, 9, -1, 'on'), 
(230, 9, -1, 'off'), 
(230, 5, -1, 'on'), 
(230, 5, -1, 'off'), 
(115, 12, -1, 'on'), 
(115, 12, -1, 'off'), 
(115, 9, -1, 'on'), 
(115, 9, -1, 'off'), 
(115, 5, -1, 'on'), 
(115, 5, -1, 'off'), 
(90, 12, -1, 'on'), 
(90, 12, -1, 'off'), 
(90, 9, -1, 'on'), 
(90, 9, -1, 'off'), 
(90, 5, -1, 'on'), 
(90, 5, -1, 'off'), 
(264, 12, -1, 'on'), 
(264, 12, -1, 'off'), 
(264, 9, -1, 'on'), 
(264, 9, -1, 'off'), 
(264, 5, -1, 'on'), 
(264, 5, -1, 'off')]