は、誰もが、これがうまく働いている私の理由を説明しようとすることができ、（）のwheres句は

Question

これを失敗とは奇妙である含めます。 Include（）は.Where節では機能しません。何か案は？

例外：

SELECT [t].[TaskId], [t].[CategoryId], [t].[Description], [t].[Name], [t].[Timestamp], [t.Category].[CategoryId], [t.Category].[Description], [t.Category].[Name], [t.Category].[Timestamp], [t.Category].[UserId], [t.Category.ApplicationUser].[Id], [t.Category.ApplicationUser].[AccessFailedCount], [t.Category.ApplicationUser].[ConcurrencyStamp], [t.Category.ApplicationUser].[Email], [t.Category.ApplicationUser].[EmailConfirmed], [t.Category.ApplicationUser].[LockoutEnabled], [t.Category.ApplicationUser].[LockoutEnd], [t.Category.ApplicationUser].[NormalizedEmail], [t.Category.ApplicationUser].[NormalizedUserName], [t.Category.ApplicationUser].[PasswordHash], [t.Category.ApplicationUser].[PhoneNumber], [t.Category.ApplicationUser].[PhoneNumberConfirmed], [t.Category.ApplicationUser].[SecurityStamp], [t.Category.ApplicationUser].[TwoFactorEnabled], [t.Category.ApplicationUser].[UserName], [c].[CategoryId], [c].[Description], [c].[Name], [c].[Timestamp], [c].[UserId], [a].[Id], [a].[AccessFailedCount], [a].[ConcurrencyStamp], [a].[Email], [a].[EmailConfirmed], [a].[LockoutEnabled], [a].[LockoutEnd], [a].[NormalizedEmail], [a].[NormalizedUserName], [a].[PasswordHash], [a].[PhoneNumber], [a].[PhoneNumberConfirmed], [a].[SecurityStamp], [a].[TwoFactorEnabled], [a].[UserName] 
FROM [Tasks] AS [t] 
INNER JOIN [Categories] AS [t.Category] ON [t].[CategoryId] = [t.Category].[CategoryId] 
LEFT JOIN [AspNetUsers] AS [t.Category.ApplicationUser] ON [t.Category].[UserId] = [t.Category.ApplicationUser].[Id] 
INNER JOIN [Categories] AS [c] ON [t].[CategoryId] = [c].[CategoryId] 
LEFT JOIN [AspNetUsers] AS [a] ON [c].[UserId] = [a].[Id] 
ORDER BY [t.Category].[UserId] 

モデル：：SQL Serverに対して実行されたときにうまく働いている

at lambda_method(Closure , InternalEntityEntry) 
    at Microsoft.EntityFrameworkCore.ChangeTracking.Internal.SimpleNonNullableDependentKeyValueFactory`1.TryCreateFromCurrentValues(InternalEntityEntry entry, TKey& key) 
    at Microsoft.EntityFrameworkCore.Query.Internal.WeakReferenceIdentityMap`1.CreateIncludeKeyComparer(INavigation navigation, InternalEntityEntry entry) 
    at Microsoft.EntityFrameworkCore.Query.Internal.QueryBuffer.IncludeCore(Object entity, INavigation navigation) 
    at Microsoft.EntityFrameworkCore.Query.Internal.QueryBuffer.Include(QueryContext queryContext, Object entity, IReadOnlyList`1 navigationPath, IReadOnlyList`1 relatedEntitiesLoaders, Int32 currentNavigationIndex, Boolean queryStateManager) 
    at Microsoft.EntityFrameworkCore.Query.Internal.QueryBuffer.Include(QueryContext queryContext, Object entity, IReadOnlyList`1 navigationPath, IReadOnlyList`1 relatedEntitiesLoaders, Boolean queryStateManager) 
    at Microsoft.EntityFrameworkCore.Query.Internal.GroupJoinInclude.Include(Object entity) 
    at Microsoft.EntityFrameworkCore.Query.QueryMethodProvider.<_GroupJoin>d__26`4.MoveNext() 
    at System.Linq.Enumerable.<SelectManyIterator>d__163`3.MoveNext() 
    at System.Linq.Enumerable.WhereSelectEnumerableIterator`2.MoveNext() 
    at Microsoft.EntityFrameworkCore.Query.Internal.LinqOperatorProvider.<_TrackEntities>d__15`2.MoveNext() 
    at Microsoft.EntityFrameworkCore.Query.Internal.LinqOperatorProvider.ExceptionInterceptor`1.EnumeratorExceptionInterceptor.MoveNext() 
    at System.Collections.Generic.List`1..ctor(IEnumerable`1 collection) 
    at System.Linq.Enumerable.ToList[TSource](IEnumerable`1 source) 
    at _:line 56 

生成されたSQL最後に

public class Task 
{ 
    [Key] 
    public int TaskId { get; set; } 
    public string Name { get; set; } 
    public string Description { get; set; } 
    public DateTime Timestamp { get; set; } 
    public int CategoryId { get; set; } 

    public virtual Category Category { get; set; } 
} 

public class Category 
{ 
    [Key] 
    public int CategoryId { get; set; } 
    public string Name { get; set; } 
    public string Description { get; set; } 
    public DateTime Timestamp { get; set; } 

    public string UserId { get; set; } 
    [ForeignKey("UserId")] 
    public virtual ApplicationUser ApplicationUser { get; set; } 

    public virtual ICollection<Task> Tasks { get; set; } 
} 

public class ApplicationUser : IdentityUser 
{ 
    public virtual ICollection<Category> Categories { get; set; } 
} 

Answer 1

は、私が解決することができました半日後の問題は無駄になった。私は.Include（）と.Where（）で目的の結果を得ることができませんでしたが、これが私のために働いています。私が非常に興味があるので、インクルード（）と.Where（）で動作させる方法を見つけたら教えてください。

return _db.Tasks 
        .Where(t => t.Category.ApplicationUser.UserName == username) 
        .Select(t => new 
        { 
         t, 
         t.Category 
        }) 
        .AsEnumerable() 
        .Select(t => t.t) 
        .ToList();