C++を使用して成績のパーセンテージを取得する方法は？

Question

私はC++での初心者ですので、私は本当にここで問題

#include<iostream> 
using namespace std; 

int main() { 
    double majorexam,score,long1exam,long2exam,longexam,shortquiz,short1quiz,short2quiz,short3quiz,grade; 

    cout<<"Input Major Exam Grade : ";cin>>majorexam; 
    cout<<"Input Long 1 Exam Grade : ";cin>>long1exam; 
    cout<<"Input Long 2 Exam Grade : ";cin>>long2exam; 
    cout<<"Input Short 1 Quiz Grade : ";cin>>short1quiz; 
    cout<<"Input Short 2 Quiz Grade : ";cin>>short2quiz; 
    cout<<"Input Short 3 Quiz Grade : ";cin>>short3quiz; 

    majorexam = score*.04; 
    longexam = (long1exam+long2exam)*.03; 
    shortquiz = (short1quiz+short2quiz+short3quiz)*.03; 

    grade = (majorexam+longexam+shortquiz)*100; 

    cout<<"Final Grade : "<<grade; 
    return 0; 
} 

が2の式 等級= 40％、主要な試験+ 30％の平均を使用して、学生の等級を計算するプログラムを書くだあなたの助けが必要長い試験+ 3つの短いクイズの平均30％。

2つの長い試験の平均、3つの短いクイズの平均を学生の学年度で表示します。生徒が合格したか失敗したかを示すメッセージも表示します。合格は75％です。

Answer 1

// try this 
    // this should work as you want 

    #include<iostream> 
    using namespace std; 

int main() { 
    double majorexam,score,long1exam,long2exam,longexam,shortquiz,short1quiz,short2quiz,short3quiz,grade; 

    cout<<"Input Major Exam Grade : ";cin>>majorexam; 
    cout<<"Input Long 1 Exam Grade : ";cin>>long1exam; 
    cout<<"Input Long 2 Exam Grade : ";cin>>long2exam; 
    cout<<"Input Short 1 Quiz Grade : ";cin>>short1quiz; 
    cout<<"Input Short 2 Quiz Grade : ";cin>>short2quiz; 
    cout<<"Input Short 3 Quiz Grade : ";cin>>short3quiz; 

    score = majorexam*.04; 
    double aveLongExam=(long1exam+long2exam)/2; 
    longexam = (aveLongExam)*.03; 
    double aveShortExam=(short1quiz+short2quiz+short3quiz)/3; 
    shortquiz = (aveShortExam)*.03; 
    grade = (score+longexam+shortquiz)*100; 
    cout<<"Ave of Quiz:: "<<aveShortExam<<" Ave of Long Exam :: " 
    <<aveLongExam<<endl; 
    cout<<"Final Grade : "<<grade; 
    return 0; 
}