配列を使用してMysqlテーブルのデータを更新します

Question

現在、print_r（）によって出力されるとき、次のような配列があります。 MySQLのテーブルは以下のようになります

$arr = Array 
(
    [14] => Array 
     (
      [url] => AllConsuming.net 
      [da] => 48 
      [pa] => 54.4 
      [moz_rank] => 5.1 
      [linksln] => 2123 
      [equity] => 1318 
      [alexa_rank] => 1725106 
      [a_links] => 197 
      [a_cnt] => GB 
      [a_cnt_rank] => 123484 
      [sem_rush_domain] => notfound 
      [sr_rank] => 0 
      [sr_kwords] => 0 
      [sr_traffic] => 0 
      [sr_costs] => 0 
      [sr_ulinks] => 514 
      [sr_hlinks] => 4154 
      [sr_dlinks] => 12732 
      [cf] => 34 
      [tf] => 21 
      [ebl] => 108777 
      [ref_domains] => 1113 
     ) 
[15] => Array 
    (
     [url] => TravelIntelligence.net 
     [da] => 31.7 
     [pa] => 33.3 
     [moz_rank] => 2.9 
     [linksln] => 1 
     [equity] => 1 
     [alexa_rank] => 4265239 
     [a_links] => 98 
     [a_cnt] => N/A 
     [a_cnt_rank] => N/A 
     [sem_rush_domain] => notfound 
     [sr_rank] => 0 
     [sr_kwords] => 0 
     [sr_traffic] => 0 
     [sr_costs] => 0 
     [sr_ulinks] => 1 
     [sr_hlinks] => 3 
     [sr_dlinks] => 3542 
     [cf] => 22 
     [tf] => 19 
     [ebl] => 6368 
     [ref_domains] => 531 
    ) 

）

：

Mysql table

私は、それぞれの分野に属する各要素の値をMySQLのテーブルにこのデータを更新したいです。配列のキー、すなわち14,15はMySQLテーブルの主キーです。

私はいくつかの天才が私にこの問題を解決するのを助けることを願っています。

ありがとうございます。あなたはプリペアドステートメントを構築するためにforeachを使用して$arrを繰り返すことができ

Answer 1

ための大きな絵です：配列のキーのための

<?php 
$arr = array(
     "14" => array(
       "url" => "AllConsuming.net", 
       "da" => 48, 
       "pa" => 54.4, 
       "moz_rank" => 5.1, 
       "linksln" => 2123, 
       "equity" => 1318, 
       "alexa_rank" => 1725106, 
       "a_links" => 197, 
       "a_cnt" => "GB", 
       "a_cnt_rank" => 123484, 
       "sem_rush_domain" => "notfound", 
       "sr_rank" => 0, 
       "sr_kwords" => 0, 
       "sr_traffic" => 0, 
       "sr_costs" => 0, 
       "sr_ulinks" => 514, 
       "sr_hlinks" => 4154, 
       "sr_dlinks" => 12732, 
       "cf" => 34, 
       "tf" => 21, 
       "ebl" => 108777, 
       "ref_domains" => 1113, 
      ), 
     "15" => array(
      "url" => "TravelIntelligence.net", 
      "da" => 31.7, 
      "pa" => 33.3, 
      "moz_rank" => 2.9, 
      "linksln" => 1, 
      "equity" => 1, 
      "alexa_rank" => 4265239, 
      "a_links" => 98, 
      "a_cnt" => "N/A", 
      "a_cnt_rank" => "N/A", 
      "sem_rush_domain" => "notfound", 
      "sr_rank" => 0, 
      "sr_kwords" => 0, 
      "sr_traffic" => 0, 
      "sr_costs" => 0, 
      "sr_ulinks" => 1, 
      "sr_hlinks" => 3, 
      "sr_dlinks" => 3542, 
      "cf" => 22, 
      "tf" => 19, 
      "ebl" => 6368, 
      "ref_domains" => 531 
     ) 
    ); 

$yourTableColumnArray = array("url", "cost", "categroy_1", "categroy_2", "categroy_3", "language", "f_n", "publishers", "da", "tf", "sr_traffic", "pa", "moz_rank", "linksln", "equity", "alexa_rank", "a_links", "a_cnt", "a_cnt_rank"); 

foreach($arr as $key => $value){ 
    $id = $key; 
    $columnAndValue = array(); 
    foreach($value as $k => $val){ 
     if(in_array($val, $yourTableColumnArray)){ 
      $columnAndValue[$k] = $val; 
     } 
    } 
    if(!empty($columnAndValue)){ 
     //your query like below: 
     $query = "UPDATE yourTableName SET"; 
     foreach($columnAndValue as $ky => $vl){ 
      $query .= " ".$ky."=".$vl; 
      end($columnAndValue); 
      if(key($columnAndValue) != $ky){ 
       $query .= ","; 
      } 

     } 
     $query .= " where out_id = $id"; 
     echo $query."<br>"; //just to know, the actual query formed for the current array(for 14 or 15) 

     // now code here to execute your query with $query variable 

    } 
    $columnAndValue = array(); 
} 

出力

= 14クエリは次のようになります。

UPDATE yourTableName SET sr_rank = 0、sr_kwords = 0、sr_traffic = 0、sr_costs = 0ここでout_id = 14

配列のキーのための210

は= 15、クエリは次のようになります。

UPDATE yourTableName SETはsr_rank = 0、sr_kwords = 0、sr_traffic = 0、sr_costs = 0 out_id = 15

Answer 2

、次のように：あなたはとにかくJSONなどのデータを投稿する場合

/** @var \PDO $dbHandle */ 

foreach ($arr as $id => $row) { 

    $row['out_id'] = $id; 

    $setInstructions = array_map(function ($key) { 
     return "'$key' = :$key"; 
    }, array_keys($row)); 

    $columnNamesWithSemicolon = array_map(function ($key) { 
     return ":$key"; 
    }, array_keys($row)); 

    $result = $dbHandle->prepare("UPDATE your_table SET " . implode(',', $setInstructions) . " WHERE out_id = :out_id"); 

    $result->execute(array_combine($columnNamesWithSemicolon, array_values($row))); 
} 

Answer 3

foreach($arr as $key=>$val) 
{ 
    $paramquery = array(); 
    $paramquery['primarykey'] = $key; 
    $paramquery['goes on your column name'] = $val_every_row['every key matched column']; 
    ------ goes on your column and fill it with your column data 


    INSERT OR UPDATE HERE 
    $this->model->whateverfunction($paramquery); 

} 

そのかなり簡単、そのつもりが容易になります。しかし、これはあなたがコンセプトの下に使用することができます@Poojaそれ