'Break' Outside Loop - Python - Number Guess Game

Question

2番目のbreakコマンドでこのエラーが発生します。なぜこうなった？ それは言う：

SyntaxError: 'break' outside loop 

はここに私のコードです：

import random 
import easygui 

secrets = random.randint(1, 200) 
secret = random.randint(1, 100) 
guess = 0 
tries = 0 

easygui.msgbox("""AHOY! I'm the Dreaded Pirate Roberts, and I have a secret! It is a number from 1 to 99. I'll give you 10 tries.""") 

while guess != secret and tries < 10: 
    guess = easygui.integerbox("What's yer guess, matey?") 
    if not guess: break 
    if guess < secret: 
     easygui.msgbox(str(guess) + " is too low, ye scurvy dog!") 
    elif guess > secret: 
     easygui.msgbox(str(guess) + " is too high, landlubber!") 
    tries = tries + 1 

if guess == secret: 
    easygui.msgbox("Avast! Ye got it! My secret is: **** ** ****! NO MATTER WHAT ****** SAYS, **** *****!!!!!!!!!!!!!!!!!") 

else: 
    easygui.msgbox("No more guesses! Better luck next time, matey!") 
    easygui.msgbox("Now, since ye lost, ye can try 1-50.") 

    while guess != secrets and tries < 15: 
     guess = easygui.integerbox("What's yer guess, matey?") 
     if not guess: break 
    if guess < secrets: 
     easygui.msgbox(str(guess) + " is too low, ye scurvy dog!") 

    elif guess > secrets: 
     easygui.msgbox(str(guess) + " is too high, landlubber!") 
    tries = tries + 1 

秒 "推測されていない場合：ブレークを" 誤りがあるものについてです。 誰かが説明できますか？

Answer 1

エラーの説明を読む

>>> if True: break 
SyntaxError: 'break' outside loop 

は、あなたがそれはあなたのインデントを修正whileループ