'on clause'内の 'userc.u_id'列が不一致

Question

私はCodeigniterを使用していますが、保存されているすべてのカスタムフィールドを持つロールID 3のすべてのユーザーを取得しようとしています。何らかの理由で、私は

" '節' 上で 不明な列 'userc.u_id'"

でデータベースエラーが発生します

$this->db->join('(SELECT GROUP_CONCAT(data) AS custom_data, id AS dataid, u_id 
    FROM ea_user_cfields userc 
    GROUP BY id) AS tt', 'userc.u_id = ea.id','left'); 
    $this->db->join('(SELECT GROUP_CONCAT(name) AS custom_name, id AS customid 
    FROM ea_customfields AS cf 
    GROUP BY id) AS te', 'userc.c_id = cf.id','left'); 
    $this->db->where('id_roles', $customers_role_id); 



    return $this->db->get('ea_users ea')->result_array(); 

実際のクエリ：

SELECT * FROM (`ea_users` ea) 

LEFT JOIN (SELECT GROUP_CONCAT(data) AS custom_data, id AS dataid, u_id FROM 
ea_user_cfields userc GROUP BY id) AS tt ON `userc`.`u_id` = 
`ea`.`id` 

LEFT JOIN (SELECT GROUP_CONCAT(name) AS 
custom_name, id AS customid FROM ea_customfields AS cf GROUP BY id) AS 
te ON `userc`.`c_id` = `cf`.`id` WHERE `id_roles` = '3' 

Answer 1

以下を使用しますコードが役立つかもしれません。

SELECT * FROM (`ea_users` ea) 

LEFT JOIN (SELECT GROUP_CONCAT(data) AS custom_data, id AS dataid, u_id FROM 
ea_user_cfields userc GROUP BY id) AS tt ON tt.`u_id` = 
`ea`.`id` 

LEFT JOIN (SELECT GROUP_CONCAT(name) AS 
custom_name, id AS customid FROM ea_customfields AS cf GROUP BY id) AS 
te ON tt.`c_id` = `cf`.`id` WHERE `id_roles` = '3'