私は問題は場所にwhereHas
で次の関数Eloquentのための方法はありますか?一致する結果のみを取得することはありますか?私は町/都市が一致する結果を望むのに対し
select * from `services` where exists
(select * from `conditions` inner join `condition_service` on `conditions`.`id` = `condition_service`.`condition_id` where `services`.`id` = `condition_service`.`service_id` and `id` in (13, 14) and `conditions`.`deleted_at` is null)
and exists
(select * from `service_locations` inner join `service_location_service` on `service_locations`.`id` = `service_location_service`.`service_location_id` where `services`.`id` = `service_location_service`.`service_id` and
(`town` like 'manchester' or `city` like 'manchester' or `town` like 'crewe' or `city` like 'crewe')
and `service_locations`.`deleted_at` is null) and `services`.`deleted_at` is null
を生成
public function index(Request $request)
{
$results = Service::whereHas('conditions', function ($query) use ($request){
$query->whereIn('id', $request->conditions);
})
->whereHas('locations', function ($query) use ($request){
$ran = false;
foreach($request->locations as $location)
{
if(!$ran)
{
$query->Where('town', 'like', '%'.$location.'%')
->orWhere('city', 'like', '%'.$location.'%');
}
else
{
$query->orWhere('town', 'like', '%'.$location.'%')
->orWhere('city', 'like', '%'.$location.'%');
}
$ran = true;
}
})
->with('types', 'contacts', 'locations.datetimes')->toSql();
dd($results);
}
を持っているが、すべての結果を戻します。これを達成するための最良の方法は何ですか?
パラメータグルーピングを使用して、恐ろしい '$ ran'フラグを並べ替えることもできます。https://laravel.com/docs/5.4/queries#parameter-grouping –