未定義シンボル

Question

消毒クランの「未定義」を使用している場合、このコードが有効になって打ち鳴らすの「未定義の動作」消毒剤と罰金コンパイル：

➜ ~ cat test.cc 
#include <iostream> 

int main(int argc, char **argv) { 
    // Won't compile if next line will be uncommented! 
    // std::cout << "Hello, World!" << std::endl; 
    int k = 0x7fffffff; 
    k += argc; 
    return 0; 
} 
➜ ~ clang++ -fsanitize=address -fsanitize=undefined test.cc 

をしかし、私はそれが爆発述べ行コメントを解除する場合：

~ clang++ -fsanitize=address -fsanitize=undefined test.cc 
Undefined symbols for architecture x86_64: 
    "___ubsan_handle_dynamic_type_cache_miss", referenced from: 
     _main in test-5f28d3.o 
     std::__1::basic_ostream<char, std::__1::char_traits<char> >& std::__1::endl<char, std::__1::char_traits<char> >(std::__1::basic_ostream<char, std::__1::char_traits<char> >&) in test-5f28d3.o 
     std::__1::basic_ostream<char, std::__1::char_traits<char> >& std::__1::__put_character_sequence<char, std::__1::char_traits<char> >(std::__1::basic_ostream<char, std::__1::char_traits<char> >&, char const*, unsigned long) in test-5f28d3.o 
     std::__1::ostreambuf_iterator<char, std::__1::char_traits<char> > std::__1::__pad_and_output<char, std::__1::char_traits<char> >(std::__1::ostreambuf_iterator<char, std::__1::char_traits<char> >, char const*, char const*, char const*, std::__1::ios_base&, char) in test-5f28d3.o 
    "___ubsan_vptr_type_cache", referenced from: 
     _main in test-5f28d3.o 
     std::__1::basic_ostream<char, std::__1::char_traits<char> >& std::__1::endl<char, std::__1::char_traits<char> >(std::__1::basic_ostream<char, std::__1::char_traits<char> >&) in test-5f28d3.o 
     std::__1::basic_ostream<char, std::__1::char_traits<char> >& std::__1::__put_character_sequence<char, std::__1::char_traits<char> >(std::__1::basic_ostream<char, std::__1::char_traits<char> >&, char const*, unsigned long) in test-5f28d3.o 
     std::__1::ostreambuf_iterator<char, std::__1::char_traits<char> > std::__1::__pad_and_output<char, std::__1::char_traits<char> >(std::__1::ostreambuf_iterator<char, std::__1::char_traits<char> >, char const*, char const*, char const*, std::__1::ios_base&, char) in test-5f28d3.o 
ld: symbol(s) not found for architecture x86_64 
clang: error: linker command failed with exit code 1 (use -v to see invocation) 

クランバージョンを：

➜ ~ clang --version 
Apple LLVM version 8.0.0 (clang-800.0.38) 
Target: x86_64-apple-darwin15.5.0 
Thread model: posix 
InstalledDir: /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin 

詳細コンパイラ出力はhereです。

私は間違っていますか？

Answer 1

問題はAppleのclangの代わりにllvmサイトのclang/llvmバイナリを使用して解決しました。