再帰呼び出しを元に戻す方法は？

Question

私の仕事は、次の出力を生成する関数を記述することです：

This was written by call number 1. 
This was written by call number 2. 
This was written by call number 3. 
This was written by call number 4. 
This was written by call number 5. 
This was ALSO written by call number 5. 
This was ALSO written by call number 4. 
This was ALSO written by call number 3. 
This was ALSO written by call number 2. 
This was ALSO written by call number 1. 

これは、数5に限定されるものではなく、プログラムがユーザからの任意の入力を取ることができ、それが出力その数よ。

は、ここで私がこれまで持っているものです。

void function_call(int number); 
int main(){ 
    int userInput; 
    cout<<"Please enter a digit: "; 
    cin>>userInput; 

    function_call(userInput); 
} 

void function_call(int number){ 
    if (number == 1){ 
     cout<<"This was written by call number "<<number<<"."<<endl; 
    } 

    else{ 

     function_call(number - 1); 
     cout<<"This was written by call number "<<number<<"."<<endl; 
    } 

} 

私の現在のコードは、最初の部分が、数字が減っていない第二部を出力します。出力の2番目の部分が表示されるようにするにはどうすればよいですか？ function_call(1,userInput)を呼び出すとき

Answer 1

は、これを試してみてください：

void function_call(int curr,int last) 
{ 
    if (curr <= last) 
    { 
     cout<<"This was written by call number "<<curr<<"."<<endl; 
     function_call(curr+1,last); 
     cout<<"This was ALSO written by call number "<<curr<<"."<<endl; 
    } 
}