列を水平に変換するPIVOT

Question

ID、名前、値の3つの列ファイルがあります。

1,Brand,sports 
1,Color,White 
1,Gender,Male 
1,Logo,yes 
1,width,10 
4,Brand,Running 
4,width,12 
4,Fits,Lose 
3,catgegory,shoe 
3,Color,blue 
3,Color,white 
3,primarycolor,blue 
5,size,M 
5,Brand,Sports 
5,Brand,Running 

私は2

それが印刷されたテキスト値を持つピボットテーブルに似ては、それはExcelを使用して行うことができない、列1、列に基づいて水平形式にこれを変換しようとしていますピボットは、値の合計/カウントだけを許可します。

これはUNIXで生成できますか？

,Brand,Color,Gender,Logo,width,Fits,catgegory,primarycolor,size 
1,sports,White,Male,yes,10,,,, 
4,Running,,,,12,Lose,,, 
3,,blue/white,,,,,shoe,blue, 
5,Sports/Running,,,,,,,,M 

Answer 1

入力

akshay@db-3325:/tmp$ cat data.txt 
1,Brand,sports 
1,Color,White 
1,Gender,Male 
1,Logo,yes 
1,width,10 
4,Brand,Running 
4,width,12 
4,Fits,Lose 
3,catgegory,shoe 
3,Color,blue 
3,primarycolor,blue 
5,size,M 
5,Brand,Running 

スクリプト

akshay@db-3325:/tmp$ cat pivot.awk 
{ 
    id=$1; name=$2; value=$3 
    ids[id]; 
    # this is to retain order 
    if(!(name in tmp)){ tmp[name]; names[++c]=name; } 
    values[id,name] = value 
} 
END { 
    # comment below line if you hide "id" 
    printf "id" 

    for (name in names) { 
     printf "%s%s",OFS,names[name] 
    } 
    print "" 
    for (id in ids) { 
     printf "%s",id 
     for (name in names) { 
      printf "%s%s",OFS,values[id,names[name]] 
     } print "" 
    } 
} 

実行と出力

akshay@db-3325:/tmp$ awk -v FS=, -v OFS=, -f pivot.awk data.txt 
id,Brand,Color,Gender,Logo,width,Fits,catgegory,primarycolor,size 
1,sports,White,Male,yes,10,,,, 
3,,blue,,,,,shoe,blue, 
4,Running,,,,12,Lose,,, 
5,Running,,,,,,,,M 

これは順

akshay@db-3325:/tmp$ cat pivot_with_order.awk 
{ 
    id=$1; name=$2; value=$3 

    # this is to retain order 
    if(!(id in itmp)){ itmp[id]; ids[++i]=id; } 
    if(!(name in tmp)){ tmp[name]; names[++c]=name; } 

    values[id,name] = value 
} 
END { 
    # uncomment below line if you want to display "id" 
    # printf "id" 

    for (name in names) { 
     printf "%s%s",OFS,names[name] 
    } 
    print "" 
    for (id in ids) { 
     printf "%s",ids[id] 
     for (name in names) { 
      printf "%s%s",OFS,values[ids[id],names[name]] 
     } print "" 
    } 
} 

出力

akshay@db-3325:/tmp$ awk -v FS=, -v OFS=, -f pivot_with_order.awk data.txt 
,Brand,Color,Gender,Logo,width,Fits,catgegory,primarycolor,size 
1,sports,White,Male,yes,10,,,, 
4,Running,,,,12,Lose,,, 
3,,blue,,,,,shoe,blue, 
5,Running,,,,,,,,M 

Answer 2

のExcel VBAを含む予想O/Pと同様のO/Pの生成：

Sub Pivot() 

    Dim rngData, rngOut, r, c, dR, dC 
    Set dR = CreateObject("scripting.dictionary") 
    Set dC = CreateObject("scripting.dictionary") 

    Set rngData = ActiveSheet.Range("A2:C2") '<< first row of input 
    Set rngOut = ActiveSheet.Range("G2")  '<< where to put output 

    Do While Application.CountA(rngData) > 0 
     r = rngData(1) 
     c = rngData(2) 
     If Not dR.exists(r) Then 
      dR.Add r, dR.Count + 1 
      rngOut.Offset(dR.Count, 0) = r 
     End If 
     If Not dC.exists(c) Then 
      dC.Add c, dC.Count + 1 
      rngOut.Offset(0, dC.Count) = c 
     End If 

     With rngOut.Offset(dR(r), dC(c)) 
      'if already has a value, add a newline separator 
      .Value = .Value & IIf(.Value <> "", vbLf, "") & rngData(3) 
     End With 
     Set rngData = rngData.Offset(1, 0) 
    Loop 

End Sub 

Answer 3

のPython 2.7に

を

list.csvがあると仮定すると：un.pyで

1,Brand,sports 
1,Color,White 
1,Gender,Male 
1,Logo,yes 
1,width,10 
4,Brand,Running 
4,width,12 
4,Fits,Lose 
3,catgegory,shoe 
3,Color,blue 
3,Color,white 
3,primarycolor,blue 
5,size,M 
5,Brand,Sports 
5,Brand,Running 

Pythonコード：

# up.py 
# 
import csv 
rowid={}; colid={}; tab={}; rowTitle=[]; colTitle=[] 
with open('list.csv', 'rb') as csvfile: 
    v = csv.reader(csvfile) 
    for row in v: 
    rowid[row[0]]=1; colid[row[1]]=1; k=row[0]+"@"+row[1] 
    if tab.has_key(k): 
     tab[k]=tab[k]+"/"+row[2]   
    else: 
     tab[k]=row[2] 

rowTitle=rowid.keys(); colTitle=colid.keys() 
rowTitle.sort(); colTitle.sort(); 

s="" 
for j in colTitle: s=s+","+j 
print s 
for i in rowTitle: 
    s=i 
    for j in colTitle: 
    k=i+"@"+j 
    s=s+"," 
    if tab.has_key(k): 
     s=s+tab[k] 
    print s 

py un.py出力は次のようになります。Akshayたくさん

,Brand,Color,Fits,Gender,Logo,catgegory,primarycolor,size,width 
1,sports,White,,Male,yes,,,,10 
3,,blue/white,,,,shoe,blue,, 
4,Running,,Lose,,,,,,12 
5,Sports/Running,,,,,,,M,