私は入力と同じ組み合わせの下したOracle

Question

内の文字列を剥ぎ取り、あなただけの、それらを考慮すべき値に過ぎないしたと仮定すると

COMPANY-ID_ABC_123   ==> This should give three outputs (COMPANY-ID,ABC,123) 
COMPANY-ID     ==> this should give give three outputs such as (COMPANY-ID,null,null) 
COMPANY-ID-FLAG    ==> this should give give three outputs such as (COMPANY-ID,FLAG,null) 
COMPANY-ID-FLAG-ES  ==> this should give give three outputs such as (COMPANY-ID,FLAG,ES) 
COMPANY-ID-ES    ==> this should give give three outputs such as (COMPANY-ID,ES,null) 
IOB-2003    ==> if i give any other string other than the above , it has to just display (IOB-2003,null,null) 

Answer 1

の下に説明したように、出力変数を返すための機能で私を助けてください複数のif-elsif-endステートメントでハードコードします。それ以外の場合は、入力文字列を解析する必要があります。それを解析しなければならない場合は、最初にCOMPANY-IDからハイフンを削除し、 ' - 'や '_'の文字列を解析します。

CREATE OR REPLACE PROCEDURE getVal 
    (string_in IN varchar2, 
     string_out1 OUT varchar2, 
     string_out2 OUT varchar2, 
     string_out3 OUT varchar2) 
AS 
    string_out1 := 'IOB-2003'; 
    string_out2 := 'null'; 
    string_out3 := 'null'; 

BEGIN 

    IF string_in = 'COMPANY-ID_ABC_123' THEN 
     string_out1 := 'COMPANY-ID'; 
     string_out2 := 'ABC'; 
     string_out3 := '123'; 

    ELSIF string_in = 'COMPANY-ID' THEN 
     string_out1 := 'COMPANY-ID'; 

    ELSIF string_in = 'COMPANY-ID-FLAG' THEN 
     string_out1 := 'COMPANY-ID'; 
     string_out2 := 'FLAG'; 

    ELSIF string_in = 'COMPANY-ID-FLAG-ES' THEN 
     string_out1 := 'COMPANY-ID'; 
     string_out2 := 'FLAG'; 
     string_out3 := 'ES'; 

    ELSIF string_in = 'COMPANY-ID-ES' THEN 
     string_out1 := 'COMPANY-ID'; 
     string_out2 := 'ES'; 

    END IF; 

END;