0
集計にフィールドを追加する方法はありますか。 (たぶん、Top_Hitを持っているかもしれませんが、実際の例を得るためにそれを管理することはできませんでした)ElasticSearchネスト集計追加のフィールドを追加
次の例では、集約で「アドレス」も取得できますか?
class Person
{
public string First_Name { get; set; }
public string Last_Name { get; set; }
public string Address { get; set; }
public int Salary { get; set; }
public Person(string first_name, string last_name, string address, int salary)
{
this.First_Name = first_name;
this.Last_Name = last_name;
this.Address = address;
this.Salary = salary;
}
public Person() { }
}
private void button4_Click(object sender, EventArgs e)
{
var defaultIndex = "persons";
var settings = new ConnectionSettings(new Uri("http://localhost:9200"))
.InferMappingFor<Person>(i => i.IndexName(defaultIndex))
.DefaultIndex(defaultIndex);
client = new ElasticClient(settings);
if (client.IndexExists(defaultIndex).Exists)
client.DeleteIndex(defaultIndex);
client.CreateIndex(defaultIndex, c => c
.Settings(s => s
.NumberOfShards(1)
)
.Mappings(m => m
.Map<Person>(mm => mm
.AutoMap()
)
)
);
Person al = new Person("Al", "Bundy", "House A", 1000);
Person bud = new Person("Bud", "Bundy", "House A", 500);
Person peggy = new Person("Peggy", "Bundy", "House A", 0);
Person kelly = new Person("Kelly", "Bundy", "House A", 100);
Person marcy = new Person("Marcy", "Darcy", "House B", 4000);
Person jefferson = new Person("Jefferson", "Darcy", "House B", 0);
client.IndexMany(new[] { al, peggy, kelly, bud, marcy, jefferson });
client.Refresh(defaultIndex);
// query the index
var result = client.Search<Person>(s => s
.Aggregations(a => a
.Terms("Families", ts => ts
.Field(o => o.Last_Name.Suffix("keyword")) // use the keyword sub-field for terms aggregation
.Size(100)
.Aggregations(aa => aa
.ValueCount("PersonCount", vc => vc
.Field(o => o.Salary)
)
)
)
)
.Size(0)
);
var names = result.Aggs.Terms("Families");
string retval = string.Empty;
foreach (var name in names.Buckets)
{
var cnt = name.ValueCount("PersonCount");
var address = ""; // how do I get the Address
retval += "* family: '" + name.Key + "' living in: " + address + " Number of persons: " + cnt.Value + Environment.NewLine;
}
MessageBox.Show(retval);
}
コードを変更すると、各家族の住所もわかります。
補足情報:1家族の各メンバーが同じ家に住んでいます。
これまでに何を試みましたか? –