ステータス[0,1]に基づいて特定の座標をソートする方法

Question

与えられたすべてのデータの中でステータス '0'または 'EMPTY'から座標を取得する方法は不思議でした。

var locations = [ 
    ['FULL',3.720185, 103.124075,1], 
    ['EMPTY',3.719693, 103.123896,0], 
    ['FULL',3.720916, 103.12492,1], 
    ['EMPTY',3.721032, 103.124532,0], 
    ['FULL',3.722299, 103.124587,1], 
    ['FULL',3.723189, 103.124706,1], 
    ['FULL',3.725067, 103.124593,1] 
    ]; 

    for (var k=0;k<locations.length; k++) 
    { 
     if (locations[i][3]==0) { 
     var diff=getDistanceFromLatLonInKm(position.coords.latitude,position.coords.longitude,locations[k][1],locations[k][2]); 
     x.innerHTML = "<h1>Distance of nearest bin: "+ Math.min(diff)+"km</h1>"; 
     } 

これはこれまで私が試したことです。

Answer 1

各位置アレイ（falsyある）0に等しいEMPTYに等しい第1要素または第四の要素を持っているかどうかをチェックする述語関数を渡し使用Array#filter：

var locations = [ 
 
    ['FULL', 3.720185, 103.124075, 1], 
 
    ['EMPTY', 3.719693, 103.123896, 0], 
 
    ['FULL', 3.720916, 103.12492, 1], 
 
    ['EMPTY', 3.721032, 103.124532, 0], 
 
    ['FULL', 3.722299, 103.124587, 1], 
 
    ['FULL', 3.723189, 103.124706, 1], 
 
    ['FULL', 3.725067, 103.124593, 1] 
 
] 
 

 
var result = locations.filter(function (e) { 
 
    return e[0] === 'EMPTY' || !e[3] 
 
}) 
 

 
console.log(result)

.as-console-wrapper { min-height: 100%; }

Answer 2

あなたできますfilter場所：

var locations = [ 
 
    ['FULL', 3.720185, 103.124075, 1], 
 
    ['EMPTY', 3.719693, 103.123896, 0], 
 
    ['FULL', 3.720916, 103.12492, 1], 
 
    ['EMPTY', 3.721032, 103.124532, 0], 
 
    ['FULL', 3.722299, 103.124587, 1], 
 
    ['FULL', 3.723189, 103.124706, 1], 
 
    ['FULL', 3.725067, 103.124593, 1] 
 
]; 
 

 
var emptyLocations = locations.filter(function(location) { 
 
    return location[0] === 'EMPTY' || location[3] === 0; 
 
}); 
 

 
console.log(emptyLocations); 
 
// [["EMPTY", 3.719693, 103.123896, 0], ["EMPTY", 3.721032, 103.124532, 0]]