jqを使用してJSON配列をCSVに変換

Question

私はtemp.jsonというJSONファイルを持っています。

私はこの

jq -r '.users[] | keys[0] [.username, .email, ."total running apps", ."api-mock-app", .flogo, .ipaas, ."nodejs-app"] | join(", ") | @csv' temp.json` 

を試してみました。しかし、誰もが説明でき、私はエラー

q: error (at temp.json:22): Cannot index string with string "jack"` 

を取得しています

username email    total running apps api-mock-app flogo ipaas nodejs-app 
jack  jack@somewhere.com 1     0   1  0  0 
jill  jill@somewhere.com 1     0   1  0  0 

、このlilke CSVにこのJSONを変換したい

{ 
    "users": [ 
    { 
     "username": "jack", 
     "email": "jack@somewhere.com", 
     "total running apps": "1", 
     "api-mock-app": "0", 
     "flogo": "1", 
     "ipaas": "0", 
     "nodejs-app": "0" 
    }, 
    { 
     "username": "jill", 
     "email": "jill@somewhere.com", 
     "total running apps": "1", 
     "api-mock-app": "0", 
     "flogo": "1", 
     "ipaas": "0", 
     "nodejs-app": "0" 
    } 
    ] 
} 

私は間違いを犯しています。簡単に正しい答えを教えてください。

Answer 1

JQ溶液：

jq -r '(.users[0] | keys_unsorted), (.users[] | to_entries | map(.value))|@csv' temp.json 

出力：

"username","email","total running apps","api-mock-app","flogo","ipaas","nodejs-app" 
"jack","jack@somewhere.com","1","0","1","0","0" 
"jill","jill@somewhere.com","1","0","1","0","0" 

Answer 2

が、私はこれを試みたが、それは完全に働いた、

jq -r '(.users[0] | keys), (.users[] | [.username, .email, ."total running apps", ."api-mock-app", .flogo, .ipaas, ."nodejs-app"]) | @csv' temp.json 

出力形式があります。

"api-mock-app","email","flogo","ipaas","nodejs-app","total running apps","username" 
"jack","jack@somewhere.com","1","0","1","0","0" 
"jill","jill@somewhere.com","1","0","1","0","0"