私は次のようなJSONデータを持っている:JSONをデータでグループ化しますか?
{
"events":
{
"event":
[
{
"city":"Birmingham",
"state":"AL",
"country":"US",
"lat":"33.5206608",
"lng":"-86.80249",
"status":"Delivered",
"occured_at":"2012-04-06
14:17:00 UTC"
},
{
"city":"Birmingham",
"state":"AL",
"country":"US",
"lat":"33.5206608",
"lng":"-86.80249",
"status":"Out
For Delivery",
"occured_at":"2012-04-06 04:44:00 UTC"
},
{
"city":"Birmingham",
"state":"AL",
"country":"US",
"lat":"33.5206608",
"lng":"-86.80249",
"status":"Arrival
Scan",
"occured_at":"2012-04-05 19:07:00 UTC"
},
{
"city":"Doraville",
"state":"GA",
"country":"US",
"lat":"33.8981579",
"lng":"-84.2832564",
"status":"Departure
Scan",
"occured_at":"2012-04-05 17:08:00 UTC"
},
{
"city":"Doraville",
"state":"GA",
"country":"US",
"lat":"33.8981579",
"lng":"-84.2832564",
"status":"Arrival
Scan",
"occured_at":"2012-04-05 11:15:00 UTC"
},
{
"city":"Spartanburg",
"state":"SC",
"country":"US",
"lat":"34.9495672",
"lng":"-81.9320482",
"status":"Departure
Scan",
"occured_at":"2012-04-05 08:42:00 UTC"
},
{
"city":"Spartanburg",
"state":"SC",
"country":"US",
"lat":"34.9495672",
"lng":"-81.9320482",
"status":"Arrival
Scan",
"occured_at":"2012-04-05 08:21:00 UTC"
},
{
"city":"Greensboro",
"state":"NC",
"country":"US",
"lat":"36.0726354",
"lng":"-79.7919754",
"status":"Departure
Scan",
"occured_at":"2012-04-05 04:45:00 UTC"
},
{
"city":"Greensboro",
"state":"NC",
"country":"US",
"lat":"36.0726354",
"lng":"-79.7919754",
"status":"Origin
Scan",
"occured_at":"2012-04-05 00:11:00 UTC"
},
{
"city":null,
"state":null,
"country":"US",
"status":"Billing
Information Received",
"occured_at":"2012-04-04 18:20:27 UTC"
}
]
}
}
私が行うために必要なものは、グループは、市、州、国の組み合わせによってデータであるが、それでも各項目からデータを返します。
たとえば、 "Birmingham、AL、US"でグループ化しても、各イベント(つまり配信済み、配信中止、到着スキャン)のstatus
を繰り返し処理することができます。
これがJSONであるという事実は本当に無関係ですね。あなたは 'JSON.parse'を使ってそれをRubyハッシュに変換し、それを使って作業することができます(必要に応じて最後にJSONに戻す)。 – Phrogz