任意のファイルをサーバーにアップロード

Question

任意のfilevを自分のサーバーにアップロードする関数を作成します。私はインターネット上のすべてを検索しましたが、外部ライブラリを使用しないと便利なものは何も見つかりませんでした。助言がありますか？

Answer 1

は、[Iは、HTTPを使用してサーバにモバイルデバイスからのAndroidでファイルを送信するにはどうすればよい？]のこの

public int uploadFile(String sourceFileUri, String destUri) 
{ 
    String fileName = sourceFileUri; 
    Log.e("YOUR_TAG", "uploading file: " + sourceFileUri); 

    HttpURLConnection conn; 
    DataOutputStream dos; 
    String lineEnd = "\r\n"; 
    String twoHyphens = "--"; 
    String boundary = "*****"; 
    int bytesRead, bytesAvailable, bufferSize; 
    byte[] buffer; 
    int maxBufferSize = 1 * 1024 * 1024; 
    File sourceFile = new File(sourceFileUri); 

    if (!sourceFile.isFile() && !sourceFile.exists()) 
    { 
     Log.e(YOUR_TAG, "Source File not exist :" + imagepath); 
     return 0; 

    } else { 

     try 
     { 
      // open a URL connection to the Servlet 
      FileInputStream fileInputStream = new FileInputStream(sourceFile); 
      URL url = new URL(destUri); 
      // Open a HTTP connection to the URL 
      conn = (HttpURLConnection) url.openConnection(); 
      conn.setDoInput(true); // Allow Inputs 
      conn.setDoOutput(true); // Allow Outputs 
      conn.setUseCaches(false); // Don't use a Cached Copy 
      conn.setRequestMethod("POST"); 
      conn.setRequestProperty("Connection", "Keep-Alive"); 
      conn.setRequestProperty("ENCTYPE", "multipart/form-data"); 
      conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); 
      conn.setRequestProperty("file", fileName); 
      dos = new DataOutputStream(conn.getOutputStream()); 
      dos.writeBytes(twoHyphens + boundary + lineEnd); 
      dos.writeBytes("Content-Disposition: form-data; name=\"file\";filename=\"" + fileName + "\"" + lineEnd); 
      dos.writeBytes(lineEnd); 
      bytesAvailable = fileInputStream.available(); 
      bufferSize = Math.min(bytesAvailable, maxBufferSize); 
      buffer = new byte[bufferSize]; 
      bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

      while (bytesRead > 0) 
      { 
       dos.write(buffer, 0, bufferSize); 
       bytesAvailable = fileInputStream.available(); 
       bufferSize = Math.min(bytesAvailable, maxBufferSize); 
       bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      } 

      dos.writeBytes(lineEnd); 
      dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 
      serverResponseCode = conn.getResponseCode(); 
      String serverResponseMessage = conn.getResponseMessage(); 
      Log.i(YOUR_TAG, "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode); 

      if (serverResponseCode == 200) 
      { 
       Log.d(YOUR_TAG, "success: " + sourceFileUri); 
       //do your stuff here 
      } 
      fileInputStream.close(); 
      dos.flush(); 
      dos.close(); 

     } catch (MalformedURLException ex) { 

      ex.printStackTrace(); 
      Log.e(YOUR_TAG, "error: " + ex.getMessage(), ex); 

     } catch (Exception e) { 

      e.printStackTrace(); 
      Log.e(YOUR_TAG, "Exception : " + e.getMessage(), e); 

     } 
     return serverResponseCode; 
    } 
} 

Answer 2

try { 
      String uploadId = UUID.randomUUID().toString(); 

      //Creating a multi part request 
      new MultipartUploadRequest(this, uploadId, UPLOAD_URL) 
        .addFileToUpload(path, "f_url") //Adding file 
        .addHeader("Authorization", "Bearer " + token) //Adding token 
        .setNotificationConfig(new UploadNotificationConfig()) 
        .setMaxRetries(2) 
        .startUpload(); //Starting the upload 

     } catch (Exception exc) { 
      Toast.makeText(this, exc.getMessage(), Toast.LENGTH_SHORT).show(); 
     }