アルファベットをどのように反復するのですか？

Question

アルファベットを反復処理して、文字Zを超えて続けるにはどうすればよいですか？例えば ​​- 、B、C ... Y、X、AA、AB、AC、広告

momenentで、これは私の配列

letters = [ 
      "a","b","c","d","e","f","g","h","i","k", 
      "l","m","n","o","p","q","r","s","t","u", 
      "v","w","x","y","z", "aa", "ab", "ac", "ad", "ae", 
      "af", "ag", "ah", "ai", "aj", "ak", "al", "am", "an", 
      "ao", "ap", "aq", "ar", "as", "at", "au", "av","aw", "ax", "ay", 
      "az", "ba", "bb", "bc", "bd", "be", "bf", "bg", "bh", "bi", 
      "bj", "bk", "bl", "bm", "bn", "bo", "bp", "bq", "br", "bs", "bt", 
      "bu", "bv","bw", "bx", "by", "bz","ca","cb","cc","cd","ce", 
      "cf","cg","ch","ci","cj","ck","cl","cm","cn","co","cp", 
      "cq","cr","cs","ct","cu","cv","cw"] 

ですが、私はそれがループ内で作成したいです。

Answer 1

あなたはこれを試すことができます。

import string 

letters = list(string.ascii_lowercase) 

letters.extend([i+b for i in letters for b in letters]) 

print letters 

をループするために、二重を使用することにより、我々は、リスト内包での反復を置くことができるスペースを節約し、より神託であることを除いて、我々は通常、希望のようにアルファベットを反復処理します。

Answer 2

string.ascii_lowercaseは小文字のすべてを保持しているため、1つのループ（1文字の文字列）または2つの文字（2文字の文字列）で繰り返し処理することができます。これは：

import string 
list = [] 
for c in string.ascii_lowercase: 
    list.append(c) 

for c1 in string.ascii_lowercase: 
    for c2 in string.ascii_lowercase: 
     list.append(c1+c2) 

print(list) 

Answer 3

stringモジュールがトリックを行います。

import string 
alphabets=list(string.ascii_lowercase) 
output=[] # output list 
for a in alphabets: 
    output.append(a) 
for a in alphabets: 
    for b in alphabets: 
     output.append('%s%s' % (a,b)) 
print output