この質問は、類似のタイトル(replace NA in an R vector with adjacent values)の投稿に関連しています。私は、データフレーム内の列をスキャンして、NAの値を隣接するセルの値に置き換えたいと考えています。前述のポストでは、解決策は、隣接するベクトル(例えば、データ行列の隣接要素)からの値ではなくNAを置き換えることであったが、固定値のための条件付き置換であった。以下は私の問題の再現可能な例である:列のNAを隣接列の値に置き換えてください。
UNIT <- c(NA,NA, 200, 200, 200, 200, 200, 300, 300, 300,300)
STATUS <-c('ACTIVE','INACTIVE','ACTIVE','ACTIVE','INACTIVE','ACTIVE','INACTIVE','ACTIVE','ACTIVE',
'ACTIVE','INACTIVE')
TERMINATED <- c('1999-07-06' , '2008-12-05' , '2000-08-18' , '2000-08-18' ,'2000-08-18' ,'2008-08-18',
'2008-08-18','2006-09-19','2006-09-19' ,'2006-09-19' ,'1999-03-15')
START <- c('2007-04-23','2008-12-06','2004-06-01','2007-02-01','2008-04-19','2010-11-29','2010-12-30',
'2007-10-29','2008-02-05','2008-06-30','2009-02-07')
STOP <- c('2008-12-05','4712-12-31','2007-01-31','2008-04-18','2010-11-28','2010-12-29','4712-12-31',
'2008-02-04','2008-06-29','2009-02-06','4712-12-31')
TEST < - data.frame(UNIT、STATUS、TERMINATED、START、STOP) TEST
UNIT STATUS TERMINATED START STOP
1 NA ACTIVE 1999-07-06 2007-04-23 2008-12-05
2 NA INACTIVE 2008-12-05 2008-12-06 4712-12-31
3 200 ACTIVE 2000-08-18 2004-06-01 2007-01-31
4 200 ACTIVE 2000-08-18 2007-02-01 2008-04-18
5 200 INACTIVE 2000-08-18 2008-04-19 2010-11-28
6 200 ACTIVE 2008-08-18 2010-11-29 2010-12-29
7 200 INACTIVE 2008-08-18 2010-12-30 4712-12-31
8 300 ACTIVE 2006-09-19 2007-10-29 2008-02-04
9 300 ACTIVE 2006-09-19 2008-02-05 2008-06-29
10 300 ACTIVE 2006-09-19 2008-06-30 2009-02-06
11 300 INACTIVE 1999-03-15 2009-02-07 4712-12-31
#using the syntax for a conditional replace and hoping it works :/
TEST$UNIT[is.na(TEST$UNIT)] <- TEST$STATUS; TEST
UNIT STATUS TERMINATED START STOP
1 1 ACTIVE 1999-07-06 2007-04-23 2008-12-05
2 2 INACTIVE 2008-12-05 2008-12-06 4712-12-31
3 200 ACTIVE 2000-08-18 2004-06-01 2007-01-31
4 200 ACTIVE 2000-08-18 2007-02-01 2008-04-18
5 200 INACTIVE 2000-08-18 2008-04-19 2010-11-28
6 200 ACTIVE 2008-08-18 2010-11-29 2010-12-29
7 200 INACTIVE 2008-08-18 2010-12-30 4712-12-31
8 300 ACTIVE 2006-09-19 2007-10-29 2008-02-04
9 300 ACTIVE 2006-09-19 2008-02-05 2008-06-29
10 300 ACTIVE 2006-09-19 2008-06-30 2009-02-06
11 300 INACTIVE 1999-03-15 2009-02-07 4712-12-31
結果は次のようになります。
UNIT STATUS TERMINATED START STOP
1 ACTIVE ACTIVE 1999-07-06 2007-04-23 2008-12-05
2 INACTIVE INACTIVE 2008-12-05 2008-12-06 4712-12-31
3 200 ACTIVE 2000-08-18 2004-06-01 2007-01-31
4 200 ACTIVE 2000-08-18 2007-02-01 2008-04-18
5 200 INACTIVE 2000-08-18 2008-04-19 2010-11-28
6 200 ACTIVE 2008-08-18 2010-11-29 2010-12-29
7 200 INACTIVE 2008-08-18 2010-12-30 4712-12-31
8 300 ACTIVE 2006-09-19 2007-10-29 2008-02-04
9 300 ACTIVE 2006-09-19 2008-02-05 2008-06-29
10 300 ACTIVE 2006-09-19 2008-06-30 2009-02-06
11 300 INACTIVE 1999-03-15 2009-02-07 4712-12-31
多分try $ UNIT [is.na(TEST $ UNIT)] < - TEST $ STATUS [is.na(TEST $ UNIT)]; TEST ' – Seth
データフレームの列内に型を混在させることはできません。 –