複数のXML形式のSQL Server単一テーブル

Question

SELECT 
    consent_type, state_code, 
    suburb, sex_code, postcode, 
    CarerPrimary, CarerResidence, CarerRelationship, 
    service_type_outlet_codeno, 
    last_service_date, service_hours, 
    to_date, from_date 
FROM 
    TABLEX 

この単一のテーブルから次のXML形式を取得するにはどうすればよいですか？最も紛らわしいのはCarerPrimary,CarerResidence、CarerRelationship部分です。この表には複数のクライアントの情報が含まれているため、クライアントごとにservice_userの部分が一度表示されます。ありがとう。

<agency> 
    <service_user consent_type="1" state_code="2" suburb="Croydon" sex_code="1" postcode="3136"> 
     <service_user_response value="1" question_fieldname="CarerPrimary"/> 
     <service_user_response value="1" question_fieldname="CarerResidence"/> 
     <service_user_response value="9" question_fieldname="CarerRelationship"/> 
     <service_user_outlet service_type_outlet_codeno="8376784" last_service_date="02/9/2016" > 
      <service_hours service_hours="240" to_date="15/8/2016" from_date="09/8/2016"/> 
      <service_hours service_hours="90" to_date="02/9/2016" from_date="02/9/2016"/> 
     </service_user_outlet> 
    </service_user> 
    <service_user .... > 
    </service_user> 
</agency> 

新しいコード、

SELECT PostalCode AS [@Postcode] 
     ,IIF (HC.HasCarer = 'true', 'Y', 'N') as [@has_carer_type] 
     ,convert(date, [BirthDate], 111) AS [@BirthDate] 
     ,'N' as [@birth_date_est_ind] 
     ,IIF (new_gender = 6, 3, new_gender) AS [@sex_code] 
     --SLK 
     ,City AS [@Suburb] 
     ,DEX.[dbo].[CRM2DEX]('State',[new_Address1State], 0) AS [@StateCode] 
     ,'Y' as [@consent_type] 

     --,CONCAT ([FirstName], ' ' + [MiddleName]) AS GivenName 
    -- ,[LastName] AS FamilyName 
    -- ,cb.new_ClientID AS ClientId 

     /********service_user_response*******/ 
     ,HC.CarerPrimary AS [service_user_response/@value] 
     ,'CarerPrimary' AS [service_user_response/@question_fieldname] 
     ,HC.CarerResidence AS [service_user_response/@value] 
     ,'CarerResidence' AS [service_user_response/@question_fieldname] 
     ,dex.dbo.CRM2QDC('Relationship', default, HC.new_Relationship) AS [service_user_response/@value] 
     ,'CarerRelationship' AS [service_user_response/@question_fieldname] 
     --,IIF (new_CarerAgeGroup IS NULL, 99, new_CarerAgeGroup) AS CarerAgeGroup 
     ,IIF (new_indigenoustatus = 9, NULL, new_indigenoustatus) AS [service_user_response/@value] 
     ,'IndigenousStatus' AS [service_user_response/@question_fieldname] 
     ,COALESCE (Country.[new_Code], '0003') AS [service_user_response/@value] 
     ,'BirthCountry' AS [service_user_response/@question_fieldname] 
     ,COALESCE (Lang.[new_Code], '0002') AS [service_user_response/@value] 
     ,'Language' AS [service_user_response/@question_fieldname] 
     ,new_interpreter AS [service_user_response/@value] 
     ,'InterpreterServices' AS [service_user_response/@question_fieldname] 
     ,new_communicationmethod AS [service_user_response/@value] 
     ,'CommunicationMethod' AS [service_user_response/@question_fieldname] 
     ,IIF (cb.new_livingarrangements = 9, 99, cb.new_livingarrangements) AS [service_user_response/@value] 
     ,'LivingArrangements' AS [service_user_response/@question_fieldname] 
     ,cb.new_residentialsetting AS [service_user_response/@value] 
     ,'ResidentialSetting' AS [service_user_response/@question_fieldname] 
     ,new_employmentstatus AS [service_user_response/@value] 
     ,'LabourForceStatus' AS [service_user_response/@question_fieldname] 
     ,IIF (new_primaryincomesource = 7, 97, new_primaryincomesource) AS [service_user_response/@value] 
     ,'IncomeSource' AS [service_user_response/@question_fieldname] 
     --,(SELECT IIF (Disability IS NULL, 'false', 'true') from HasDisablity where ClientID = CB.ContactId) AS HasDisabilities 

     --,IIF (new_client is NULL, NULL, (select coalesce (new_name, null) FROM Health AS D where D.new_contact = CB.ContactId for xml path ('DisabilityCode'), type)) AS Disabilities 
     --,(SELECT IIF (new_name IS NULL, NULL, (select H2.new_name from Health AS H2 where H2.new_contact = CB.ContactId 
     -- for xml path ('DisabilityCode'), type)) FROM Health AS D where D.new_contact = CB.ContactId) AS Disabilities 
-- ,DEX.[dbo].[CRM2DEX]('AccommodationType',C.new_residentialsetting, 0) AS AccommodationTypeCode 
-- ,DEX.[dbo].[CRM2DEX]('DVACardStatus',[new_DVAentitlement], 0) AS DVACardStatusCode 
     --,COALESCE (HasCarer, 'false') AS HasCarer 





-- ,DEX.[dbo].[CRM2DEX]('HouseholdComposition', C.new_livingarrangements, 0) AS HouseholdCompositionCode 

    FROM [FOCUSCRM_MSCRM].[dbo].[ContactBase] AS CB 
    INNER JOIN 
     (SELECT [ParentId] 
      ,[Line1] 
      ,[Line2] 
      ,[City] 
      ,[PostalCode] 
     FROM [FOCUSCRM_MSCRM].[dbo].[CustomerAddressBase] 
     WHERE addressNumber = 1) AS A ON CB.ContactId = A.ParentId 

    LEFT OUTER JOIN 
     (SELECT [new_countryId] 
      ,[new_name] 
      ,[new_Code] 
     FROM [FOCUSCRM_MSCRM].[dbo].[new_countryBase]) AS Country ON CB.new_CountryofBirth = Country.new_countryId 

    LEFT OUTER JOIN 
     (SELECT [new_languageId] 
      ,[new_name] 
      ,[new_Code] 
     FROM [FOCUSCRM_MSCRM].[dbo].[new_languageBase]) AS Lang ON CB.new_PreferredLanguage = Lang.new_languageId 


    LEFT OUTER JOIN 
     (SELECT new_ClientName, new_livingarrangements, new_residentialsetting 
     FROM (
     SELECT [new_ClientName] 
     ,row_number() over (Partition by new_ClientName ORDER BY ModifiedOn DESC) AS R 
     ,new_AssessmentDate 
     ,new_livingarrangements 
     ,new_residentialsetting 

     FROM [FOCUSCRM_MSCRM].[dbo].[new_assessmentBase] AS AB1 
     WHERE statecode = 0 
     ) AS T1 

     WHERE R = 1) AS C ON CB.ContactId = C.new_ClientName 

    LEFT OUTER JOIN HasCarer AS HC ON HC.new_clientname = cb.contactID 

     WHERE CB.new_clientID IN (SELECT DISTINCT new_clientID from TS) 
    and statecode = 0 

    --) AS T GROUP BY ClientID having count(ClientId)>1 

FOR XML PATH('service_user'),ROOT('agency'); 

Answer 1

サンプルデータがなければ、それは盲目飛行ですが、あなたはこのような何かを試してみてください：

SELECT 
    consent_type AS [@constent_type] 
    , state_code AS [@state_code] 
    , suburb AS [@suburb] 
    , sex_code AS [@sex_code] 
    , postcode AS [@postcode] 
    , CarerPrimary AS [service_user_response/@value] 
    ,'CarerPrimary' AS [service_user_response/@question_fieldname] 
    , CarerResidence AS [service_user_response/@value] 
    ,'CarerResidence' AS [service_user_response/@question_fieldname] 
    , CarerRelationship AS [service_user_response/@value] 
    ,'CarerRelationship' AS [service_user_response/@question_fieldname] 
    , service_type_outlet_codeno AS [service_user_outlet/@service_type_outlet_codeno] 
    , last_service_date AS [service_user_outlet/@last_service_date] 
    , service_hours AS [service_user_outlet/service_hours/@service_hours] 
    , to_date AS [service_user_outlet/service_hours/@to_date] 
    , from_date AS [service_user_outlet/service_hours/@from_date] 
FROM 
    TABLEX 
FOR XML PATH('service_user'),ROOT('agency'); 

FOR XML PATHは、列の別名としてXPathを定義することができます。属性には@記号が付けられています。

例のservice_hoursは、1:nのように見えますが、クエリはそのようには見えません。