PostgreSQLでクロス集計を作成するには？

Question

CREATE TEMP TABLE pivot(
gid SERIAL, 
zoom smallint NOT NULL, 
day timestamp with time zone NOT NULL, 
point integer NOT NULL 
); 

INSERT DATA

INSERT INTO pivot(zoom, day, point) VALUES(6,'2015-10-01',21); 
INSERT INTO pivot(zoom, day, point) VALUES(7,'2015-10-01',43); 
INSERT INTO pivot(zoom, day, point) VALUES(8,'2015-10-01',18); 
INSERT INTO pivot(zoom, day, point) VALUES(9,'2015-10-01',14); 
INSERT INTO pivot(zoom, day, point) VALUES(10,'2015-10-01',23); 
INSERT INTO pivot(zoom, day, point) VALUES(11,'2015-10-01',54); 
INSERT INTO pivot(zoom, day, point) VALUES(6,'2015-10-02',657); 
INSERT INTO pivot(zoom, day, point) VALUES(7,'2015-10-02',432); 
INSERT INTO pivot(zoom, day, point) VALUES(8,'2015-10-02',421); 
INSERT INTO pivot(zoom, day, point) VALUES(9,'2015-10-02',432); 
INSERT INTO pivot(zoom, day, point) VALUES(10,'2015-10-02',454); 
INSERT INTO pivot(zoom, day, point) VALUES(11,'2015-10-02',654); 

すべてが今まで動作するかどうかを確認できます一時テーブルを作成：

SELECT zoom, day, point 
FROM pivot 
ORDER BY 1,2; 

結果：

zoom |   day   | point 
------+------------------------+------- 
    6 | 2015-10-01 00:00:00+02 | 21 
    6 | 2015-10-02 00:00:00+02 | 657 
    7 | 2015-10-01 00:00:00+02 | 43 
    7 | 2015-10-02 00:00:00+02 | 432 
    8 | 2015-10-01 00:00:00+02 | 18 
    8 | 2015-10-02 00:00:00+02 | 421 
    9 | 2015-10-01 00:00:00+02 | 14 
    9 | 2015-10-02 00:00:00+02 | 432 
    10 | 2015-10-01 00:00:00+02 | 23 
    10 | 2015-10-02 00:00:00+02 | 454 
    11 | 2015-10-01 00:00:00+02 | 54 
    11 | 2015-10-02 00:00:00+02 | 654 
(12 rows) 

C REATE EXTENSION：

CREATE EXTENSION tablefunc; 

クロス集計クエリ

SELECT * FROM crosstab(
     'SELECT zoom, day, point 
     FROM pivot 
     ORDER BY 1,2' 
     ,$$VALUES ('2015-10-01'::timestamp), ('2015-10-02')$$) 
AS ct ("zoom" smallint, "2015-10-01" integer, "2015-10-02" integer); 

結果：私はポイントの値を返すことはできません

zoom | 2015-10-01 | 2015-10-02 
------+------------+------------ 
    6 |   | 
    7 |   | 
    8 |   | 
    9 |   | 
    10 |   | 
    11 |   | 
(6 rows) 

、クエリ自体は私の空のスポットを提供します。私は間違って何をしていますか？

編集

私はそれを他の方法を実行しようとしましたが、私はまだ上記の質問に対する答えを探しています。

SELECT * from crosstab (
    'select zoom, day, point 
    from pivot 
    order by 1,2', 
    'select distinct day from pivot order by 1') 
AS ct(zoom smallint, "2015-10-01" integer, "2015-10-02" integer); 

結果：@Abelisto提案へ

zoom | 2015-10-01 | 2015-10-02 
------+------------+------------ 
    6 |   21 |  657 
    7 |   43 |  432 
    8 |   18 |  421 
    9 |   14 |  432 
    10 |   23 |  454 
    11 |   54 |  654 
(6 rows) 

Answer 1

おかげでおよそtimestamptz、これは動作します：

SELECT * FROM crosstab(
     'SELECT zoom, day, point 
     FROM pivot 
     ORDER BY 1,2' 
     ,$$VALUES ('2015-10-01'::timestamptz), ('2015-10-02')$$) 
AS ct ("zoom" smallint, "2015-10-01" integer, "2015-10-02" integer);