whileループはelif文に達した場合に無限ループします

Question

このコードは参考用です。彼らは400ゴールドで始まり、アイテムが高すぎる場合、別のアイテムを選びたいかどうかを尋ねます。私の問題は、whileループを無限にループする余裕があるアイテムを選んだ場合、その理由がわからないことです。これはどう

shopitemsF = ["Ghostblade: 150 Damage, Cost: 700", "Thunderblade: 120 Damage, Cost: 300", "Bloodcursed Sword: 160 Damage, Cost 800"] 
    shopitemsM = ["Fire Throw: 150 Damage, Cost: 700", "Ice Wind: 120 Damage, Cost: 300", "Electric shock: 160 Damage, Cost 800"] 


    print("Welcome to the shop.") 
    print('') 
    if character == "Fighter": 
     g = ', ' 
     print(g.join(shopitemsF)) 
     time.sleep(1) 
    elif character == "Mage": 
     g = ', ' 
     print(g.join(shopitemsM)) 
     time.sleep(1) 

    shopchoice = input("Please pick another item? ") 
    print('') 

    while True: 
     for text2 in shopitemsF: 
      if shopchoice in text2: 
       print(text2) 
       if int(text2[-3:]) >= gold: 
        print("You need another", int(text2[-3:]) - gold, "gold.") 
        shopchoice = input("Please pick another item? ") 
        break      
       elif int(text2[-3:]) <= gold: 
        print("You have purchased,", text2[:-11]+".") 
        x = (int(text2[-21:-18])) 


     for text2 in shopitemsM: 
      if shopchoice in text2: 
       print(text2) 
       if int(text2[-3:]) >= gold: 
        print("You need another", int(text2[-3:]) - gold, "gold.") 
        shopchoice = input("Please pick another item? ") 
        break 
       elif int(text2[-3:]) <= gold: 
        print("You have purchased,", text2[:-11]+".") 
        x = (int(text2[-21:-18])) 

Answer 1

：あなたは、変数foundを作成

shopitemsF = ["Ghostblade: 150 Damage, Cost: 700", "Thunderblade: 120 Damage, Cost: 300", "Bloodcursed Sword: 160 Damage, Cost 800"] 
shopitemsM = ["Fire Throw: 150 Damage, Cost: 700", "Ice Wind: 120 Damage, Cost: 300", "Electric shock: 160 Damage, Cost 800"] 


print("Welcome to the shop.") 
print('') 
if character == "Fighter": 
    g = ', ' 
    print(g.join(shopitemsF)) 
    time.sleep(1) 
elif character == "Mage": 
    g = ', ' 
    print(g.join(shopitemsM)) 
    time.sleep(1) 

shopchoice = input("Please pick another item? ") 
print('') 

found = False 
while found != True: 
    for text2 in shopitemsF: 
     if shopchoice in text2: 
      print(text2) 
      if int(text2[-3:]) >= gold: 
       print("You need another", int(text2[-3:]) - gold, "gold.") 
       shopchoice = input("Please pick another item? ") 
       break      
      elif int(text2[-3:]) <= gold: 
       print("You have purchased,", text2[:-11]+".") 
       x = (int(text2[-21:-18])) 
       found = True 


    for text2 in shopitemsM: 
     if shopchoice in text2: 
      print(text2) 
      if int(text2[-3:]) >= gold: 
       print("You need another", int(text2[-3:]) - gold, "gold.") 
       shopchoice = input("Please pick another item? ") 
       break 
      elif int(text2[-3:]) <= gold: 
       print("You have purchased,", text2[:-11]+".") 
       x = (int(text2[-21:-18])) 
       found = True 

はfalseに設定し、アイテムが偽それを維持します見つけない限り。その後、while found != True:は、アイテムが高価すぎるインスタンスのループを維持します。しかし、彼らが商品を購入した場合、見つかったものはtrueに設定され、ループから外れます

Answer 2

shopchoiceをもう一度尋ねることは決してありません。最初に選択したものは永遠に残っています。 shopchoice = input (...)ステートメントをwhileループの先頭に1回だけ入れてください。 ）あなたは店から出る方法を考えなければならない;）