標準偏差の計算に何が問題なのですか？

Question

標準偏差を見つけるためのコードが間違っています。私のコードは、ユーザー入力からの標準偏差を見つけるはずです。私は数字1 2 3をタイプし、この数字セットの標準偏差は1ですが、どこが間違っていたのですか？また、私は未使用の変数の束がそれらを気にしないことを知っています。

import java.util.Scanner; 

public class readFromKeyboard { 

    public static void main(String[] args) { 


     Scanner input = new Scanner(System.in); 

     String inStr = input.next(); 
     int n; 
     int i; 
     int count=0; 
     int min = Integer.MAX_VALUE; 
     int max = Integer.MIN_VALUE; 
     double average=0; 
     int sum; 
     double deviation = 0; 
     int total; 
     int temp = 0; 



     while (!inStr.equals("EOL")) { 
      count++; 
      n = Integer.parseInt(inStr); 
      min = Math.min(min, n); 
      max = Math.max(max, n); 
      System.out.printf("%d ", n); 
      inStr = input.next(); 
      average += n; 
      temp += Math.pow(n - average, 2); 

     } 

     deviation = temp 
     average = average/count; 

     System.out.println("\n The average of these numbers is " + average); 
     System.out.printf("The list has %d numbers\n", count); 
     System.out.printf("The minimum of the list is %d\n", min); 
     System.out.printf("The maximum of the list is %d\n", max); 
     System.out.printf("The standard deviation of the list is %d\n", temp); 

     input.close(); 


    } 
} 

Answer 1

import java.util.ArrayList; 
import java.util.Scanner; 

public class ReadFromKeyboard { 

    public static void main(String[] args) { 

     Scanner input = new Scanner(System.in); 

     String inStr = input.next(); 
     int n = 0; 
     int i; 
     int count = 0; 
     int min = Integer.MAX_VALUE; 
     int max = Integer.MIN_VALUE; 
     double average = 0; 
     int sum; 
     double deviation = 0; 
     int total; 
     double temp = 0;// correction here because it must store double or float value 

     ArrayList<Integer> n1 = new ArrayList<Integer>();// i used this to store all entered values 

     while (!inStr.equals("EOL")) { 
      count++; 
      n = Integer.parseInt(inStr); 
      min = Math.min(min, n); 
      max = Math.max(max, n); 
      System.out.printf("%d ", n); 
      n1.add(n); 
      inStr = input.next(); 
      average += n; 

     } 

     average = average/count; // this will give you final average 

     for (int j = 0; j < count; j++) { 
      temp += Math.pow(n1.get(j) - average, 2); 
     } 
     //System.out.println("\n" + temp + " " + count); 
     deviation = Math.sqrt(temp/count); // this is your standard deviation 

     //System.out.println(deviation); 

     System.out.println("\n The average of these numbers is " + average); 
     System.out.printf("The list has %d numbers\n", count); 
     System.out.printf("The minimum of the list is %d\n", min); 
     System.out.printf("The maximum of the list is %d\n", max); 
     System.out.println("The standard deviation of the list is " + deviation); 

     input.close(); 

    } 
} 

Answer 2

1つの変数の標準偏差がhereと定義されています。観測値と平均値の差の平方和の平方根を取る必要があります。

//in the loop 
temp += Math.pow(n - average, 2) 
//outside the loop 
deviation = Math.pow(temp/count,0.5) //or alternatively Math.sqrt() 

これは、必要なものを提供します。