swift3でtableviewとsearchbarcontrollerを使用してスコープ検索を作成する方法

Question

こんにちはすべて、tableviewとserchbarcontrollerを使用してスコープ検索を設計しました。これを達成するために、以下のコードを使用しましたが、何とか実際の出力を返してくれません。助けを求めてありがとうございました。

出力：

here is my output's ScreenShot

コード：

import UIKit 

class SearchBookVC: UIViewController, UITableViewDelegate, UITableViewDataSource, UISearchResultsUpdating, UISearchBarDelegate { 

@IBOutlet weak var tableview: UITableView! 

struct Books { 
    var name = String() 
    var board = String() 
    var classname = String() 
    var area = String() 
    var city = String() 
    } 

    var books = [Books(name: "Physics", board: "CBSE",classname:"XI",area:"Karnataka",city:"Bangalore"), 
       Books(name:"English",board:"CBSE",classname:"X",area:"Maharashtra",city:"pune"), 
       Books(name:"biology",board:"IB",classname:"XII",area:"Gujarat",city:"Rajkot"), 

       Books(name:"chemistry",board:"IB",classname:"X",area:"Gujarat",city:"Ahmedabad"), 

       Books(name:"Maths",board:"ICSE",classname:"IX",area:"Maharashtra",city:"Mumbai"), 
       Books(name:"Science",board:"ICSE",classname:"XII",area:"Karnataka",city:"Mysore") 
       ] 
    var filteredBooks = [Books]() 

    let searchController = UISearchController(searchResultsController: nil) 



    override func viewDidLoad() { 
    super.viewDidLoad() 

     filteredBooks = books 

     searchController.searchResultsUpdater = self 
     searchController.dimsBackgroundDuringPresentation = false 
     definesPresentationContext = true 
     tableview.tableHeaderView = searchController.searchBar 

     searchController.searchBar.scopeButtonTitles = ["All","Name", "Board", "Class", "Area","City"] 

     searchController.searchBar.delegate = self 

     self.tableview.register(mycell.self, forCellReuseIdentifier: "cell") 


    // Do any additional setup after loading the view. 
} 

func applySearch(searchText: String, scope: String = "All") { 


    if searchController.searchBar.text! == "" 
    { 
     filteredBooks = books.filter { book in 
      let nameofbook = (scope == "All") || (book.name == scope) || (book.board == scope) || (book.classname == scope) || (book.area == scope) || (book.city == scope) 
      return nameofbook 
    } 
    } 
     else 
     { 
      filteredBooks = books.filter { book in 
       let nameofbook = (scope == "All") || (book.name == scope) || (book.board == scope) || (book.classname == scope) || (book.area == scope) || (book.city == scope) 
       return nameofbook && book.name.lowercased().contains(searchText.lowercased()) && book.board.lowercased().contains(searchText.lowercased()) && book.classname.lowercased().contains(searchText.lowercased()) && book.area.lowercased().contains(searchText.lowercased()) && book.city.lowercased().contains(searchText.lowercased()) 
      } 
     } 
    self.tableview.reloadData() 
} 
func updateSearchResults(for searchController: UISearchController) { 

    let searchBar = searchController.searchBar 
    let selectedScope = searchBar.scopeButtonTitles![searchBar.selectedScopeButtonIndex] 
    applySearch(searchText: searchController.searchBar.text!,scope: selectedScope) 
} 
func searchBar(_ searchBar: UISearchBar, selectedScopeButtonIndexDidChange selectedScope: Int) { 
    applySearch(searchText: searchController.searchBar.text!,scope: searchBar.scopeButtonTitles![selectedScope]) 
} 



func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int { 
    return self.filteredBooks.count 
} 
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell { 
    let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! mycell 

    cell.bookname?.text = self.filteredBooks[indexPath.row].name 
    cell.Boardname?.text = self.filteredBooks[indexPath.row].board 
    cell.classtitle?.text = self.filteredBooks[indexPath.row].classname 

    return cell 
} 
func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) { 
    print("Row \(indexPath.row) selected") 
} 

} 

Answer 1

あなたはそれをこの方法を試すことができます：

1. 自動補完テキストベースの配列を作成しますフィールド、データソースごとに1つ。
2. これらのテキストフィールドを最初は非表示にします。
3. 値を選択して検索ボタンをクリックした後、対応するテキストフィールドを表示させます。

問題が発生した場合は、ご意見をお寄せください。