Pandas DataFrameスタイルを使用して列を色付けする（Python 3）

Question

http://pandas.pydata.org/pandas-docs/stable/style.htmlのチュートリアルに従うと、カラー列のパンダデータフレームのセルの背景を色づけしようとしています。

パンダのみを使用してこれを行う正しい方法は何ですか？

s = """ 
    num_markers num_contamination color 
0   2.0    0.0 #db5f57 
1  100.0    47.0 #db7157 
2  104.0    102.0 #db8457 
3  102.0    100.0 #db9657 
4   NaN    NaN #dba957 
5   51.0    0.0 #dbbb57 
6   NaN    NaN #dbce57 
7   92.0    63.0 #d6db57 
8   NaN    NaN #c4db57 
9   56.0    42.0 #b1db57 
""" 
df = pd.read_clipboard() #Copy and paste then do this 
D_idx_color = df["color"].to_dict() 
df.style.apply(lambda x:"background-color: %s"%D_idx_color[x], subset=["color"]) 

--------------------------------------------------------------------------- 
TypeError         Traceback (most recent call last) 
/Users/jespinoz/anaconda/lib/python3.6/site-packages/IPython/core/formatters.py in __call__(self, obj) 
    309    method = get_real_method(obj, self.print_method) 
    310    if method is not None: 
--> 311     return method() 
    312    return None 
    313   else: 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/formats/style.py in _repr_html_(self) 
    190  def _repr_html_(self): 
    191   """Hooks into Jupyter notebook rich display system.""" 
--> 192   return self.render() 
    193 
    194  def _translate(self): 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/formats/style.py in render(self) 
    415   the rendered HTML in the notebook. 
    416   """ 
--> 417   self._compute() 
    418   d = self._translate() 
    419   # filter out empty styles, every cell will have a class 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/formats/style.py in _compute(self) 
    481   r = self 
    482   for func, args, kwargs in self._todo: 
--> 483    r = func(self)(*args, **kwargs) 
    484   return r 
    485 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/formats/style.py in _apply(self, func, axis, subset, **kwargs) 
    489   data = self.data.loc[subset] 
    490   if axis is not None: 
--> 491    result = data.apply(func, axis=axis, **kwargs) 
    492   else: 
    493    result = func(data, **kwargs) 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/core/frame.py in apply(self, func, axis, broadcast, raw, reduce, args, **kwds) 
    4150      if reduce is None: 
    4151       reduce = True 
-> 4152      return self._apply_standard(f, axis, reduce=reduce) 
    4153    else: 
    4154     return self._apply_broadcast(f, axis) 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/core/frame.py in _apply_standard(self, func, axis, ignore_failures, reduce) 
    4246    try: 
    4247     for i, v in enumerate(series_gen): 
-> 4248      results[i] = func(v) 
    4249      keys.append(v.name) 
    4250    except Exception as e: 

<ipython-input-155-3bf2a87dcd1f> in <lambda>(x) 
    14 df = pd.read_clipboard() #Copy and paste then do this 
    15 D_idx_color = df["color"].to_dict() 
---> 16 df.style.apply(lambda x:"background-color: %s"%D_idx_color[x], subset=["color"]) 

/Users/jespinoz/anaconda/lib/python3.6/site-packages/pandas/core/generic.py in __hash__(self) 
    829  def __hash__(self): 
    830   raise TypeError('{0!r} objects are mutable, thus they cannot be' 
--> 831       ' hashed'.format(self.__class__.__name__)) 
    832 
    833  def __iter__(self): 

TypeError: ("'Series' objects are mutable, thus they cannot be hashed", 'occurred at index color') 

Answer 1

私はあなたが単に個々の要素に、あなたの関数を適用するapplymapを使用することができ、辞書に色を変換する必要はありませんだと思います。

df.style.applymap(lambda x:"background-color: %s"%x, subset=['color']) 

あなたはcolor列に応じて、すべての要素を色付けしたい場合は、

def to_color(x): 
    return ["background-color: %s"%i for i in df.color] 
df.style.apply(to_color, axis=0)