TypeError： 'in <string>'は、メソッドではなく、左オペランドとして文字列が必要です。PYTHON

Question

コードを実行しようとすると、TypeErrorが表示されます。 状態：TypeError： 'in'は、メソッドではなく、左のオペランドとして文字列を要求します。

正確にはどういう意味か、それを修正する方法がわかりません。

エラーがで作成されたコードは次のとおりです。

from tkinter import * 
from tkinter import messagebox 

def saveCustomer() : 

    ClientID = ClientIDVar.get() 
    ClientID = ClientID.ljust(50) 
    Surname = SurnameVar.get() 
    Surname = Surname.ljust(50) 
    Forename = ForenameVar.get() 
    Forename = Forename.ljust(50) 
    Age = AgeVar.get() 
    Age = Age.ljust(50) 
    Gender = GenderVar.get() 
    Gender = Gender.ljust(50) 

    #lengthcheck 
    ClientID = ClientIDVar.get() 
    if len(ClientID) > 5 : 
     messagebox.showerror("Error","Too many characters in ClientID") 
     return 
    Surname = SurnameVar.get() 
    if len(Surname) > 20 : 
     messagebox.showerror("Error","Too many characters in Surname") 
     return 
    Forename = ForenameVar.get() 
    if len(Forename) > 15 : 
     messagebox.showerror("Error","Too many characters in Forename") 
     return 
    Age = AgeVar.get() 
    if len(Age) > 2 : 
     messagebox.showerror("Error","Too many characters in Age") 
     return 
    Gender = GenderVar.get() 
    if len(Gender) > 2 : 
     messagebox.showerror("Error","Too many characters in Gender") 
     return 
    #presencecheck 
    if ClientID == "": 
     messagebox.showerror("Error","Please enter characters into ClientID") 
     return 
    if Surname == "": 
     messagebox.showerror("Error","Please enter characters into Surname") 
     return 
    if Forename == "": 
     messagebox.showerror("Error","Please enter characters into Forename") 
     return 
    if Age == "": 
     messagebox.showerror("Error","Please enter characters into Age") 
     return 
    if Gender == "": 
     messagebox.showerror("Error","Please enter characters into Gender") 
     return 
    #rangecheck 
    if (int(Age) < 18) or (int(Age) > 99): 
     messagebox.showerror("Error","Please enter an age between 18 and 99") 
     return 
    #typecheck 
    if not ClientID.isnumeric(): 
     messagebox.showerror("Error","Please enter alphabetical characters and numerical values into ClientID") 
     return 
    if not Surname.isalpha(): 
     messagebox.showerror("Error","Please enter alphabetical characters into Surname") 
     return 
    if not Forename.isalpha(): 
     messagebox.showerror("Error","Please enter alphabetical characters into Forename") 
     return 
    if not Age.isnumeric(): 
     messagebox.showerror("Error","Please enter numerical values into Age") 
     return 
    if not Gender.isalpha(): 
     messagebox.showerror("Error","Please enter alphabetical characters and numerical values into Gender") 
     return 







    #open the file to append - if it's not there it'll be created 
    fileObject = open("Customers.txt","a") 
    # write to the file with a newline character at the end 
    fileObject.write(ClientID + Surname + Forename + Age + Gender + "\n") 
    fileObject.close() 

    return 

def searchCustomer() : 
    Found = "N" 
    ClientID = ClientIDVar.get 
    # try opening the file for reading 
    try: 
     fileObject=open("Customers.txt","r") 

    # if it's not there then say 
    except IOError: 
     messagebox.showerror("Error","No file to read") 

    # if we did open it then let's carry on! 
    else: 
     while True: 

      recordVar=fileObject.readline() 
      # Python keeps reading till EOF then returns a blank 
      if recordVar=="": 
       fileObject.close() 
       break 

      if ClientID in recordVar[0:50] and not ClientID=="" : 
       Found = "T" 
       messagebox.showinfo("Information",str(RecordVar)) 
       break 

    if Found == "F": 
     messagebox.showerror("Error","No Customer found.") 
    return 



def makeWindow(): 
    #declared my globals here as this is the 1st routine called 
    # the other routines have to be in front of this one as they get called by it 
    # and the parser would get upset if they weren't there 

    global ClientIDVar, SurnameVar, ForenameVar, AgeVar, GenderVar 

    #here's my window 
    win = Tk() 
    win.wm_title("FitnessCentre") 
    #split into two sections then further split into a grid 
    frame1=Frame(win) 
    frame1.pack() 

    Label(frame1, text="Fitness Leisure Centre", font=("Helvetica 12    bold")).grid(row=0, column=0) 

    Label(frame1, text="ClientID").grid(row=1, column=0, sticky=W) 
    ClientIDVar=StringVar() 
    title= Entry(frame1, textvariable=ClientIDVar) 
    title.grid(row=1,column=1,sticky=W) 

    Label(frame1, text="Surname").grid(row=2, column=0, sticky=W) 
    SurnameVar=StringVar() 
    genre= Entry(frame1, textvariable=SurnameVar) 
    genre.grid(row=2,column=1,sticky=W) 

    Label(frame1, text="Forename").grid(row=3, column=0, sticky=W) 
    ForenameVar=StringVar() 
    director= Entry(frame1, textvariable=ForenameVar) 
    director.grid(row=3,column=1,sticky=W) 

    Label(frame1, text="Age").grid(row=4, column=0, sticky=W) 
    AgeVar=StringVar() 
    leadactor= Entry(frame1, textvariable=AgeVar) 
    leadactor.grid(row=4,column=1,sticky=W) 

    Label(frame1, text="Gender").grid(row=5, column=0, sticky=W) 
    GenderVar=StringVar() 
    duration= Entry(frame1, textvariable=GenderVar) 
    duration.grid(row=5,column=1,sticky=W) 

    frame2 = Frame(win) 
    frame2.pack() 

    # build my buttons in the other frame then pack them side by side 
    b1= Button(frame2, text=" Save ", command=saveCustomer) 
    b2= Button(frame2, text=" Search ", command=searchCustomer) 
    b1.pack(side=LEFT); b2.pack(side=LEFT) 

    return win 


#main program! 
win = makeWindow() 
win.mainloop() 

私が受け取った完全なエラーメッセージがされた：

Exception in Tkinter callback 
Traceback (most recent call last): 

if ClientID in recordVar[0:50] and not ClientID=="" : 
TypeError: 'in <string>' requires string as left operand, not method 

Answer 1

質問からの引用：

TypeError: 'in' requires string as left operand, not method.

だからどこかで、あなたは、左の方法ではなく、期待通りの文字列でin演算子を使用しています。エラー/スタックトレース全体を投稿していれば、どのラインがエラーを引き起こしているのか分かりました。

ClientID = ClientIDVar.get 

おそらくあなたはClientIDVar、ない（あなたが得たものである）そのgetメソッドの値を返すように望んでいた：あなたのコードのクイックスキャンで、私は、エラーがここにあると思うだろう。だから簡単な修正です - 関数を適切に呼び出す：

ClientID = ClientIDVar.get() 

Answer 2

あなたが持っている、in比較をテストするための方法を使用することはできません文字列と比較する：

if ClientID in recordVar[0:50] and not ClientID=="" : 

エラーは明らかに説明していますあなたにこの：

TypeError. It states: TypeError:'in'requires string as left operand, not method.