スプリングのjson文字列から作成されたモデルを検証する

Question

json jacksonオブジェクトマッパーを使用してjson文字列からモデルを作成しています。

私のコードはmodel.Howを準備しながら、任意のデータの不一致が例外を通してそれを設定されている場合、私はそれを行うことができますので、私はJSONを検証する従業員のオブジェクトを準備する前に

ObjectMapper mapper = new ObjectMapper(); 
    String empValue = mapper.writeValueAsString(employeeMap); 
    Employees employee = mapper.readValue(empValue, Employees.class); 

のですか？

Answer 1

あなたはgetPathReferenceに主にある、getPathとを使用してJsonMappingExceptionクラスと（com.fasterxml.jackson.databind.excパッケージの下）そのサブクラスのうち、例外のうち、方法をいくつかの貴重な情報を得ることができ

はここで2つの例です：

public class ObjectMapperTest { 
    private ObjectMapper objectMapper; 

    @Before 
    public void setup() { 
     objectMapper = new ObjectMapper(); 
    } 

    @Test 
    public void testWrongDataType() { 
     String personStr = "{\"age\":\"100Y\",\"firstName\":\"Jackson\",\"lastName\":\"Pollock\",\"gender\":\"M\"}"; 
     try { 
      objectMapper.readValue(personStr, Person.class); 
     } catch (JsonMappingException jme) { 
       System.out.println(jme.getMessage()); 
       if(jme instanceof InvalidFormatException) { 
        InvalidFormatException ife = (InvalidFormatException)jme; 
        System.out.println("Mapping failure on field:" + ife.getPathReference()); 
        System.out.println("Expected type: " + ife.getTargetType()); 
        System.out.println("provided value: " + ife.getValue()); 
       } 
     }catch (Exception e){ 
      System.out.println(e.getMessage()); 
     } 
    } 

    @Test 
    public void testUnrecognizedProperty() { 
     String personStr = "{\"gae\":\"100\",\"firstName\":\"Jackson\",\"lastName\":\"Pollock\",\"gender\":\"M\"}"; 
     try { 
      objectMapper.readValue(personStr, Person.class); 
     } catch (JsonMappingException jme) { 
      System.out.println(jme.getMessage()); 
      if(jme instanceof PropertyBindingException) { 
       PropertyBindingException pbe = (PropertyBindingException) jme; 
       System.out.println("Mapping failure on field:" + pbe.getPathReference()); 
       System.out.println("UnExpected field: " + pbe.getPropertyName()); 
      } 
     }catch (Exception e){ 
      System.out.println(e.getMessage()); 
     } 
    } 
} 

が出力されます

testUnrecognizedProperty: 
======================== 
Unrecognized field "gae" (class Person), not marked as ignorable (4 known properties: "lastName", "gender", "firstName", "age"]) 
at [Source: {"gae":"100","firstName":"Jackson","lastName":"Pollock","gender":"M"}; line: 1, column: 9] (through reference chain: Person["gae"]) 
Mapping failure on field:Person["gae"] 
UnExpected field: gae 
testWrongDataType: 
======================== 
Can not construct instance of java.lang.Integer from String value '100Y': not a valid Integer value 
at [Source: {"age":"100Y","firstName":"Jackson","lastName":"Pollock","gender":"M"}; line: 1, column: 2] (through reference chain: Person["age"]) 
Mapping failure on field:Person["age"] 
Expected type: class java.lang.Integer 
provided value: 100Y