C＃でajaxレスポンスを返すには？

Question

私はAJAXとC＃を初めて使用していますので、一緒に作業する方法を試しています。私はWebアプリケーションを構築しています。私はajax関数でC＃のメソッドを呼び出しています。すべて正常に動作すれば、私はC＃クラスに成功メッセージを返します。どうやってやるの？ これは私のAjaxの方法

<script type="text/javascript"> 


Hello(); 
    function Hello() { 
     $.ajax({ 
      type: "POST", 
      url: "Dtata.aspx/Hello", 
      contentType: "application/json; charset=utf-8", 
      dataType: "json", 
      success: function (result) { 
       response(result.d); 
      }, 
      error: function (result) { 
       alert('There is a problem processing your request'); 
      } 
     }); 
    } 


</script> 

    //Basically I want to know the success/failure value from the Ajax call and print it back to my console. 

    protected void Page_Load(object sender, EventArgs e) 
    { 


    } 

    [WebMethod] 
    public static string Hello(string name) 
    { 
     return name; 
    } 

Answer 1

では、あなたのAJAX呼び出しでも、データを渡すためにしようとしましたか？ （文字列名）..あなたのバックエンド・サービス（WebMethod属性）を引き起こすそのメソッドのparamでそれを持っている...のようなもの：

<script type="text/javascript"> 




     Hello(); 
      function Hello() { 
       $.ajax({ 
        type: "POST", 
        url: "Dtata.aspx/Hello", 
        contentType: "application/json; charset=utf-8", 
        dataType: "json", 
        data:{name:'hello'}, 
        success: function (result) { 
         response(result.d); 
         Counter() //<-- CALL OTHER AJAX METHOD TO INCREASE COUNTER ON BACK END 
        }, 
        error: function (result) { 
         alert('There is a problem processing your request'); 
        } 
       }); 
      } 


function Counter() { 
       $.ajax({ 
        type: "POST", 
        url: "Dtata.aspx/Counter", 
        contentType: "application/json; charset=utf-8", 
        dataType: "json", 

        success: function (result) { 
         console.log(result.d); 
        }, 
        error: function (result) { 
         alert('There is a problem processing your request'); 
        } 
       }); 
      } 


     </script> 

      //Basically I want to know the success/failure value from the Ajax call and print it back to my console. 
     private int _counter; 
      protected void Page_Load(object sender, EventArgs e) 
      { 


      } 

      [WebMethod] 
      public static string Hello(string name) 
      { 
       return name; 
      } 



      [WebMethod] 
       public static int Counter() 
       { 
        this._counter = this._counter +1; 
        return this._counter 
       } 

Answer 2

をあなたはAJAX呼び出しにデータを逃した：

var counter=0; 
$.ajax({ 
    type: "POST", 
    url: "Dtata.aspx/Hello", 
    contentType: "application/json; charset=utf-8", 
    dataType: "json", 
    data:{name:"test"} 
    success: function (result) { 
      //result is response from c#. you can do your trick here 
      alert(result.d); 
      if(result.d=="success"){ 
       counter++; 
      } 
    }, 
    error: function (result) { 
      alert('There is a problem processing your request'); 
    } 
});