同じテーブルの値を持つテーブルを更新します。

Question

SQLの質問。私はtable_idである適切なparent_idに対してsystem_idをpartent_idとして配置します。だから私はこれをしようとしていたが、いくつかのエラーを取得しています：

update justmarket.companies e, (Select DISTINCT company_id from justmarket.companies where parent_id = system_id) c 
set e.parent_id = c.company_id 
where e.company_id = c.company_id 

はエラーを終了：

Error Static analysis:

6 errors were found during analysis.

An expression was expected. (near "(" at position 31) Unexpected token. (near "(" at position 31) A new statement was found, but no delimiter between it and the previous one. (near "Select" at position 32) Unexpected token. (near ")" at position 112) Unexpected token. (near "c" at position 114) A new statement was found, but no delimiter between it and the previous one. (near "set" at position 117) SQL query: Documentation

update justmarket.companies e, (Select DISTINCT company_id from justmarket.companies where parent_id = system_id) c set e.parent_id = c.company_id where e.company_id = c.company_id

MySQL said: Documentation

1205 - Lock wait timeout exceeded; try restarting transaction

表： のcompany_id COMPANY_NAME SYSTEM_ID PARENT_ID 1名1 55121 0 2 Name2は52211 55121 3 NAME3 55444 55121

私が探しているもの company_id company_name system_id parent_id 1名1 55121 0 2 Name2は52211 1 3 NAME3 55444 1

Answer 1

サブクエリを使用せずに、明示的なJOIN構文を使用してみてください。

UPDATE companies AS e 
JOIN companies AS c ON e.company_id = c.company_id 
SET e.parent_id = c.company_id 
WHERE c.parent_id = c.system_id