特定の文字列を返す方法

Question

私はこのようなデータの何千もの行を持つテーブルを持っています。

note 
---- 
LB MN IM 12 18 20 CIN # EW80851R This is tJ 
ified KGM nteal icne cinac12345T Cannot locate 
NCR Last verified 06 05 14 cin number ty56478P for the front 
OD 00612 Last Verified cin#ad89521Y Me side C 05 05 14 
SPC 0 VERIFIED PD IMB cin PU12301R Last Verified 
PC PO CON FC D Verified 02/29/2016 No Copy CIN#FG62301F 

各行には、単語cinとそれに続くいくつかの文字が含まれています。例えば

：CIN # EW80851R, cinac12345T, cin number ty56478P, cin#ad89521Y, cin PU12301R, CIN#FG62301F

がどのように私は返すようにクエリを記述します。

note 
---- 
cinEW80851R 
cinac12345T 
cinty56478P 
cinad89521Y 
cinPU12301R 
CINFG62301F 

Answer 1

をXMLから少し助けを借りて、文字列パーサとクロスが適用され、あなたはあなたの全体のデータを処理することができますセット。

あなたはシンボルをいじりとしてあなただけ#持っていると仮定すると、私は2番目のレコード

Declare @YourTable table (ID int,Note varchar(max)) 
Insert into @YourTable values 
(1,'LB MN IM 12 18 20 CIN # EW80851R This is tJ ified KGM nteal icne cinac12345T Cannot locate NCR Last verified 06 05 14 cin number ty56478P for the front OD 00612 Last Verified cin#ad89521Y Me side C 05 05 14 SPC 0 VERIFIED PD IMB cin PU12301R Last Verified PC PO CON FC D Verified 02/29/2016 No Copy CIN#FG62301F'), 
(2,'L This is tJ KGM teal icne Last verified 06 05 14 for the front OD 00612 Last Verified cin#ZZ89256Y Me side C 05 05 14 SPC 0 VERIFIED PD IMB cin ZZPU12301R Last Verified PC PO CON FC D Verified 02/29/2016 No Copy CIN#ZZ62301F') 

-- Create a Mapping/Normaization Table 
Declare @Map table (MapSeq int,MapFrom varchar(25),MapTo varchar(25)) 
Insert into @Map values (1,char(13),' '),(2,char(10),' '),(3,' cin number ',' cin'),(4,' cin # ',' cin'),(5,' cin#',' cin'),(6,' cin ',' cin') 

-- Convert your Base Data to XML 
Declare @XML XML,@String varchar(max) 
Set @XML = (Select KeyID=ID,String=+' '+Note+' ' from @YourTable For XML RAW) 

-- Convert XML to Varchar(max) and Apply Global Search & Replace 
Select @String = cast(@XML as varchar(max)) 
Select @String = Replace(@String,MapFrom,MapTo) From @Map Order by MapSeq 

-- Convert Back to XML 
Select @XML = cast(@String as XML) 

-- Generate Final Results 
Select A.ID 
     ,CIN = B.Key_Value 
From (
     Select ID  = t.col.value('@KeyID', 'int') 
       ,NewString = t.col.value('@String', 'varchar(max)') 
     From @XML.nodes('/row') AS t (col) 
    ) A 
Cross Apply (Select * from [dbo].[udf-Str-Parse](A.NewString,' ') where Key_Value like 'cin%') B 

戻り

ID CIN 
1 cinEW80851R 
1 cinac12345T 
1 cinty56478P 
1 cinad89521Y 
1 cinPU12301R 
1 cinFG62301F 
2 cinZZ89256Y  << Dummy Record 
2 cinZZPU12301R << Dummy Record 
2 cinZZ62301F  << Dummy Record 

を追加したことをUDF

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimeter varchar(10)) 
--Usage: Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',') 
--  Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ') 
--  Select * from [dbo].[udf-Str-Parse]('id26,id46|id658,id967','|') 
--  Select * from [dbo].[udf-Str-Parse]('hello world. It. is. . raining.today','.') 

Returns @ReturnTable Table (Key_PS int IDENTITY(1,1), Key_Value varchar(max)) 
As 
Begin 
    Declare @XML xml;Set @XML = Cast('<x>' + Replace(@String,@Delimeter,'</x><x>')+'</x>' as XML) 
    Insert Into @ReturnTable Select Key_Value = ltrim(rtrim(String.value('.', 'varchar(max)'))) FROM @XML.nodes('x') as T(String) 
    Return 
End 

Answer 2

に注意しましょう、と長さ必要な部分は8で、この値の3〜7の部分はintエゲル - あなたは、このようにXML（XQueryを）使用しようとすることができます：あなたが提供しているテーブル部から

DECLARE @xml xml 

SELECT @xml = (
    SELECT CAST('<d>'+REPLACE(REPLACE(SUBSTRING(Note,CHARINDEX('cin',Note)+3,LEN(Note)),' ','#'),'#','</d><d>')+'</d>' as xml) 
    FROM YourTable 
    FOR XML PATH('') 
) 

SELECT t.v.value('.','nvarchar(8)')   
FROM @xml.nodes('/d') as t(v) 
WHERE LEN(t.v.value('.','nvarchar(8)')) = 8 --check if length = 8 
    AND ISNULL(t.v.value('substring(string(.), 3, 5) cast as xs:int ?','int'),0) != 0 --check if part of value is int 

は、出力は次のようになります（@ JohnCappelletiのソリューションに触発）

EW80851R 
ac12345T 
ty56478P 
ad89521Y 
PU12301R 
FG62301F 

EDITを

さらに複雑な解決策：

--Declare variables 
DECLARE @xml xml, @string nvarchar(max) = '' 
--Rows becomes one big string 
SELECT @string = @string + SUBSTRING(Note,CHARINDEX('cin',Note)+3,LEN(Note)) +' ' 
FROM YourTable y 
--CTE with all not numeric and not alphabetical charecters for normalization 
;WITH Symbols AS (
    SELECT 0 as d, 
      CHAR(0) as s, 
      1 as isUsed 
    UNION ALL 
    SELECT d+1, 
      CHAR(d+1), 
      CASE WHEN d+1 between 48 and 57 
        OR d+1 between 65 and 90 
        OR d+1 between 97 and 122 THEN 0 ELSE 1 END 
    FROM Symbols 
    WHERE d < 255 
) 
--replace all not numeric and not alphabetic 
SELECT @string = REPLACE(@string,s.s,'#') 
FROM Symbols s 
WHERE isUsed = 1 
OPTION(MAXRECURSION 0) 
--convert to xml 
SELECT @xml= CAST('<d>'+REPLACE(@string,'#','</d><d>')+'</d>' as xml) 
--convert XML to table 
SELECT t.v.value('.','nvarchar(8)')   
FROM @xml.nodes('/d') as t(v) 
WHERE LEN(t.v.value('.','nvarchar(8)')) = 8 --check if length = 8 
    AND ISNULL(t.v.value('substring(string(.), 3, 5) cast as xs:int ?','int'),0) != 0 
    --check if part of value is int