T-SQLはこのクエリで重複する列を削除します

Question

私はビュー "TableInformationView"を持っています。

USE [AdventureWorks] 
--OR ANY DATABASE 
/****** Object: View [dbo].[TableInformationView] Script Date: 01/01/2011 01:17:31 ******/ 
IF EXISTS (SELECT * 
      FROM sys.views 
      WHERE object_id = OBJECT_ID(N'[dbo].[TableInformationView]')) 
    DROP VIEW [dbo].[TableInformationView] 

GO 

/****** Object: View [dbo].[TableInformationView] Script Date: 01/01/2011 01:17:31 ******/ 
SET ANSI_NULLS ON 

GO 

SET QUOTED_IDENTIFIER ON 

GO 

CREATE VIEW [dbo].[TableInformationView] 
AS 
    SELECT C.TABLE_SCHEMA        AS SchemaName, 
     C.TABLE_NAME        AS BaseTableName, 
     CASE 
      WHEN C.TABLE_SCHEMA = 'dbo' THEN C.TABLE_NAME 
      ELSE C.TABLE_SCHEMA + '.' + C.TABLE_NAME 
     END           AS TableName, 
     C.COLUMN_NAME        AS ColumnName, 
     C.ORDINAL_POSITION       as OrdinalPosition, 
     C.COLUMN_DEFAULT       as ColumnDefault, 
     C.IS_NULLABLE        AS IsNullable, 
     C.DATA_TYPE         as DataType, 
     ISNULL(C.CHARACTER_MAXIMUM_LENGTH, 0)  as MaxLength, 
     TC.CONSTRAINT_TYPE       AS ConstraintType, 
     TC.CONSTRAINT_NAME       as ConstraintName, 
     RC.UNIQUE_CONSTRAINT_NAME     as ParentConstraintName, 
     RC.MATCH_OPTION        as MatchOption, 
     RC.UPDATE_RULE        as UpdateRule, 
     RC.DELETE_RULE        as DeleteRule, 
     TC_FK.TABLE_SCHEMA + '.' + TC_FK.TABLE_NAME 'ForeignTable' 
    FROM INFORMATION_SCHEMA.COLUMNS C 
     LEFT OUTER JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE KCU 
      ON C.TABLE_NAME = KCU.TABLE_NAME 
       AND C.COLUMN_NAME = KCU.COLUMN_NAME 
       AND C.TABLE_SCHEMA = KCU.TABLE_SCHEMA 
       AND C.ORDINAL_POSITION = KCU.ORDINAL_POSITION 
     LEFT OUTER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC 
      ON KCU.TABLE_NAME = TC.TABLE_NAME 
       AND KCU.TABLE_SCHEMA = TC.TABLE_SCHEMA 
       AND KCU.CONSTRAINT_NAME = TC.CONSTRAINT_NAME 
       AND KCU.CONSTRAINT_SCHEMA = TC.CONSTRAINT_SCHEMA 
       AND KCU.CONSTRAINT_CATALOG = TC.CONSTRAINT_CATALOG 
     LEFT OUTER JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS RC 
      ON RC.CONSTRAINT_NAME = KCU.CONSTRAINT_NAME 
       AND RC.UNIQUE_CONSTRAINT_SCHEMA = KCU.CONSTRAINT_SCHEMA 
     LEFT JOIN INFORMATION_SCHEMA.KEY_COLUMN_USAGE KCU_FK 
      ON RC.CONSTRAINT_NAME = KCU_FK.CONSTRAINT_NAME 
       AND RC.UNIQUE_CONSTRAINT_SCHEMA = KCU.CONSTRAINT_SCHEMA 
     LEFT JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC_FK 
      ON RC.UNIQUE_CONSTRAINT_NAME = TC_FK.CONSTRAINT_NAME 
       AND RC.UNIQUE_CONSTRAINT_SCHEMA = TC_FK.CONSTRAINT_SCHEMA 

GO 

ビューは、別のテーブルの外部キーである列を除いて正常に動作します。

を参照してくださいどのように

SELECT * FROM TableInformationView 
WHERE 
    TableInformationView.SchemaName + 
    TableInformationView.BaseTableName + 
    TableInformationView.ColumnName 

    IN 
    (
    select TOP 1 
     TableInformationView.SchemaName + 
     TableInformationView.BaseTableName + 
     TableInformationView.ColumnName 
    from 
    TableInformationView 
    group by 
     TableInformationView.SchemaName + 
     TableInformationView.BaseTableName + 
     TableInformationView.ColumnName 
    having COUNT(*) > 1 
) 

編集：！ は=記号が修正されましたが、これはどんな違いがありません。

誰かが私に解決策を提供して、不要な列の不要な行表現が含まれないようにすることができます。

ありがとうございます。

Answer 1

あなたはユニークなテーブルを取得するクエリを探している場合は、列の組み合わせは、このクエリを使用することができます。

SELECT * 
    FROM (
     SELECT a.*, 
       ROW_NUMBER() OVER(PARTITION BY a.SchemaName,a.BaseTableName,a.ColumnName ORDER BY TableName DESC) rnk 
      FROM TableInformationView a 
       ) a 
WHERE rnk = 1