アルファベット順のキー/値のリストをソート

Question

グラフを取得して、Y軸の下にAを、Aを上に、Zを（(0,0)の近くに）リストします。

それ石畳の混乱は、私はこれを行う方法を学んでいるが、ここに関連するコードなので、今だ：

from collections import Counter 
import matplotlib.pyplot as plt; plt.rcdefaults() 
import numpy as np 
import matplotlib.pyplot as plt 
from collections import OrderedDict 
from operator import itemgetter 

myFile = "D:/User/Documents/Data/English Words/words_alpha.txt" 

ie_prefix = {} 
ie_prefix.setdefault("letter", []) 
ie_prefix.setdefault("word",[]) 
ie_prefix.setdefault("beforec",[]) 
ie_prefix_sorted = {} 

def get_words(file_import): 
    global total_words, ie_after_c, ie_after_not_c 
    #if I don't do this and just keep the below, I get an error: 'total_words' is not defined when running the print(..., total_words, "total words and", ...) line. 
    total_words = 0 
    ie_after_not_c = 0 
    ie_after_c = 0 
    results = [] 
    with open(file_import) as inputfile: 
     for line in inputfile: 
      total_words = total_words + 1 
      if line.find("ie") != -1: 
       pos = line.find("ie") 
       ie_prefix["letter"].append(line[pos-1:pos]) 
       ie_prefix["word"].append(line.strip('\n')) 
       if line[pos-1:pos] == "c": 
        ie_prefix["beforec"].append(line.strip('\n')) 
        ie_after_c += 1 
       elif line[pos-1:pos] != "c": 
        ie_after_not_c += 1 

    ie_prefix_sorted = OrderedDict(sorted(ie_prefix.items())) 
    return ie_prefix, total_words, ie_after_not_c, ie_after_c, ie_prefix_sorted 


def create_graph(total_words, y_axis, x_axis): 
    y_pos = np.arange(len(y_axis)) 
    fig, ax = plt.subplots() 
    plt.barh(y_pos, x_axis, align='center', alpha=0.5) 
    plt.yticks(y_pos, y_axis) 
    plt.ylabel('Usage') 
    plt.title('I before E rule') 
    plt.legend() 
    plt.show() 

get_words(myFile) 

# https://stackoverflow.com/questions/20316299/formatting-output-of-counter 
ie_count = Counter(ie_prefix["letter"]) 

ie_count_sorted = sorted(ie_count) #sorted(ie_count.items()) ## THis will just sort the KEYS I believe 
ie_letters = list(ie_count_sorted) 

###  
## How to use the SORTED IE Count in the graph, so it goes from A-Z where A is at the TOP, and Z is at the BOTTOM of Y-Axis (Z closest to (0,0))? 
create_graph(total, ie_count, ie_count.values()) 

FYIここprint(ie_count)です：

Counter({'r': 2417, 't': 1771, 'l': 1304, 'f': 1034, 'd': 778, 'h': 765, 'p': 753, 'c': 729, 'n': 647, 'm': 536, 'g': 492, 's': 470, 'k': 443, 'v': 273, 'b': 260, 'z': 154, 'u': 134, 'w': 93, 'o': 75, 'x': 73, 'y': 49, 'e': 29, 'a': 26, '': 3, 'j': 2, 'i': 1})

は、私が理解することはできませんie_countをアルファベット順に並べ替える方法を説明し、値（2417,171など）をキー（文字）で保持します。

Answer 1

あなたは.itemsをソートしzipでキーと値を展開することができます

from collections import Counter 
from operator import itemgetter 

ie_count = Counter({'r': 2417, 't': 1771, 'l': 1304, 'f': 1034, 'd': 778, 'h': 765, 'p': 753, 'c': 729, 'n': 647, 'm': 536, 'g': 492, 's': 470, 'k': 443, 'v': 273, 'b': 260, 'z': 154, 'u': 134, 'w': 93, 'o': 75, 'x': 73, 'y': 49, 'e': 29, 'a': 26, '': 3, 'j': 2, 'i': 1}) 

cnts_sorted = sorted(ie_count.items(), key=itemgetter(0)) 
print(cnts_sorted) 
# [('', 3), ('a', 26), ('b', 260), ('c', 729), ('d', 778), ('e', 29), 
# ('f', 1034), ('g', 492), ('h', 765), ('i', 1), ('j', 2), ('k', 443), 
# ('l', 1304), ('m', 536), ('n', 647), ('o', 75), ('p', 753), ('r', 2417), 
# ('s', 470), ('t', 1771), ('u', 134), ('v', 273), ('w', 93), ('x', 73), 
# ('y', 49), ('z', 154)] 


letters, vals = zip(*cnts_sorted) 
print(letters) 
# ('', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 
# 'o', 'p', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z') 
print(vals) 
# (3, 26, 260, 729, 778, 29, 1034, 492, 765, 1, 2, 443, 1304, 536, 647, 75, 
# 753, 2417, 470, 1771, 134, 273, 93, 73, 49, 154)