JPAQL、連結操作

Question

私は「テクニカルライターMASTHANVALI」のような出力を得るために、次の操作を行いますしようとしています。

Exception in thread "main" java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager: Exception Description: Syntax error parsing [select concat(upper(ename) , " - ", deg)from employee]. 
[20, 25] The encapsulated expression is not a valid expression. 
[37, 40] The expression 'deg' is not valid expression. 
[54, 54] An identification variable must be provided for a range variable declaration. 
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.createQuery(EntityManagerImpl.java:1605) 
at com.tutorialspoint.eclipselink.service.ScalarandAggregateFunctions.main(ScalarandAggregateFunctions.java:14) Caused by: Exception [EclipseLink-0] (Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.JPQLException 

どうすればいいですか？

Answer 1

は、単一のqoutesで二重引用符を交換しようとすると、閉じ括弧

Query query = 
    em.createQuery("select concat(upper(ename) , ' - ', deg) from employee");