2016-10-18 8 views
-5

これは私の問題は、(!(CKの==のUID))場合は私が使用している、ここにあるすべてのコード問題は何ですか?

public class LoginActivity extends Activity { 
    private static final String TAG = RegisterActivity.class.getSimpleName(); 
    private Button btnLogin; 
    private Button btnLinkToRegister; 
    private EditText inputEmail; 
    private EditText inputPassword; 
    private ProgressDialog pDialog; 
    private SessionManager session; 
    private SQLiteHandler db; 
    String CK="admin"; 

    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_login); 

     inputEmail = (EditText) findViewById(R.id.email); 
     inputPassword = (EditText) findViewById(R.id.password); 
     btnLogin = (Button) findViewById(R.id.btnLogin); 
     btnLinkToRegister = (Button) findViewById(R.id.btnLinkToRegisterScreen); 

     // Progress dialog 
     pDialog = new ProgressDialog(this); 
     pDialog.setCancelable(false); 

     // SQLite database handler 
     db = new SQLiteHandler(getApplicationContext()); 

     // Session manager 
     session = new SessionManager(getApplicationContext()); 

     // Check if user is already logged in or not 
     if (session.isLoggedIn()) { 
      // User is already logged in. Take him to main activity 
      Intent intent = new Intent(LoginActivity.this, MainActivity.class); 
      startActivity(intent); 
      finish(); 
     } 

     // Login button Click Event 
     btnLogin.setOnClickListener(new View.OnClickListener() { 

      public void onClick(View view) { 
       String email = inputEmail.getText().toString().trim(); 
       String password = inputPassword.getText().toString().trim(); 

       // Check for empty data in the form 
       if (!email.isEmpty() && !password.isEmpty()) { 
        // login user 
        checkLogin(email, password); 
       } else { 
        // Prompt user to enter credentials 
        Toast.makeText(getApplicationContext(), 
          "Please enter the credentials!", Toast.LENGTH_LONG) 
          .show(); 
       } 
      } 

     }); 

     // Link to Register Screen 
     btnLinkToRegister.setOnClickListener(new View.OnClickListener() { 

      public void onClick(View view) { 
       Intent i = new Intent(getApplicationContext(), 
         RegisterActivity.class); 
       startActivity(i); 
       finish(); 
      } 
     }); 

    } 

    /** 
    * function to verify login details in mysql db 
    * */ 
    private void checkLogin(final String email, final String password) { 
     // Tag used to cancel the request 
     String tag_string_req = "req_login"; 

     pDialog.setMessage("Logging in ..."); 
     showDialog(); 

     StringRequest strReq = new StringRequest(Method.POST, 
       AppConfig.URL_LOGIN, new Response.Listener<String>() { 

      @Override 
      public void onResponse(String response) { 
       Log.d(TAG, "Login Response: " + response.toString()); 
       hideDialog(); 

       try { 
        JSONObject jObj = new JSONObject(response); 
        boolean error = jObj.getBoolean("error"); 

        // Check for error node in json 
        if (!error) { 
         // user successfully logged in 
         // Create login session 
         session.setLogin(true); 

である、それは動作しますが、CKは==それをuidをするときは、」doesnのt仕事、文字列CK = adminと私はadminとの単純なユーザーではなく、uid = adminもログインします。私はあなたが私のキャプチャ画像を見ることができる検証するためにLog.eを使用 you can see that CK and uid are the same but when i use (if CK==uid) it doesn't work

     // Now store the user in SQLite 
         String uid = jObj.getString("uid"); 

         JSONObject user = jObj.getJSONObject("user"); 
         String name = user.getString("name"); 
         String email = user.getString("email"); 
         String created_at = user 
           .getString("created_at"); 

         // Inserting row in users table 
         db.addUser(name, email, uid, created_at); 

         Log.e(TAG,"CK: " + CK + " user uid: " + uid); 

         // Launch main activity 
         if(!(CK==uid)){ 
          Intent intent = new Intent(LoginActivity.this, 
            MainActivity.class); 
          startActivity(intent); 
          finish(); 

         } else{ 
          Intent i = new Intent(getApplicationContext(), AllReclamationsActivity.class); 
          startActivity(i); 
          finish(); 
         } 
        } else { 
         // Error in login. Get the error message 
         String errorMsg = jObj.getString("error_msg"); 
         Toast.makeText(getApplicationContext(), 
           errorMsg, Toast.LENGTH_LONG).show(); 
        } 
       } catch (JSONException e) { 
        // JSON error 
        e.printStackTrace(); 
        Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show(); 
       } 

      } 
     }, new Response.ErrorListener() { 

      @Override 
      public void onErrorResponse(VolleyError error) { 
       Log.e(TAG, "Login Error: " + error.getMessage()); 
       Toast.makeText(getApplicationContext(), 
         error.getMessage(), Toast.LENGTH_LONG).show(); 
       hideDialog(); 
      } 
     }) { 

      @Override 
      protected Map<String, String> getParams() { 
       // Posting parameters to login url 
       Map<String, String> params = new HashMap<String, String>(); 
       params.put("email", email); 
       params.put("password", password); 

       return params; 
      } 

     }; 

     // Adding request to request queue 
     AppController.getInstance().addToRequestQueue(strReq, tag_string_req); 
    } 

私の問題は、この部分である:

// Now store the user in SQLite 
        String uid = jObj.getString("uid"); 

        JSONObject user = jObj.getJSONObject("user"); 
        String name = user.getString("name"); 
        String email = user.getString("email"); 
        String created_at = user 
          .getString("created_at"); 

        // Inserting row in users table 
        db.addUser(name, email, uid, created_at); 

        Log.e(TAG,"CK: " + CK + " user uid: " + uid); 

        // Launch main activity 
        if(!(CK==uid)){ 
         Intent intent = new Intent(LoginActivity.this, 
           MainActivity.class); 
         startActivity(intent); 
         finish(); 

        } else{ 
         Intent i = new Intent(getApplicationContext(), AllReclamationsActivity.class); 
         startActivity(i); 
         finish(); 
        } 

答えて

1

これではない整数値の文字列あなたの状態で以下の機能を使用してください:

if(!(CK.equals(uid))){ 
        Intent intent = new Intent(LoginActivity.this, 
          MainActivity.class); 
        startActivity(intent); 
        finish(); 

       } 
+0

ありがとうございます:D – Amine

関連する問題