どこからでもアクセス可能な変数

Question

私はdraw chart using google chart APIにしようとしています。このチャートはデータベースからデータを取得します。ユーザは、チャートを描画したい日付を決定することができる。 weekly, year, Mysql monthly ...等。ユーザーはMySQLのクエリは、この変数にアクセスすることはできません週、月または年を選択

エラーが変数$sql

session_start(); 
 
$data_set = $_SESSION['config']; 
 
include("inc/users/$data_set.php"); 
 

 
include('database.php'); 
 
$connection = new database(); 
 
$con2 = $connection->connect($db, $user, $pass, $host); 
 

 
$time = $_POST['tar']; 
 

 
if ($time == 'week') { 
 
    $sql = "SELECT COUNT(DISTINCT `username`) AS `count`,date(`AcctStartTime`) AS `date1` FROM `radacct` where date(AcctStartTime) = curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY AND date(AcctStartTime) < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY"; 
 
} else if ($time == 'month') { 
 
    $sql = "SELECT COUNT(DISTINCT `username`) AS `count`,date(`AcctStartTime`) AS `date1` FROM radacct 
 
    WHERE YEAR(AcctStartTime) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH) AND MONTH(AcctStartTime) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)"; 
 
} else if ($time == 'year') { 
 
    $sql = "SELECT COUNT(DISTINCT `username`) AS `count`,date(`AcctStartTime`) AS `date1` FROM radacct 
 
    WHERE YEAR(AcctStartTime) = YEAR(CURRENT_DATE - INTERVAL 1 YEAR)"; 
 
} 
 
$result = $con2->query($sql); 
 

 
while ($result2 = $result->fetch_assoc()) { 
 
    $rows[] = array("c" => array("0" => array("v" => $result2['date1'], "f" => NULL), "1" => array("v" => (int) $result2['count'], "f" => NULL))); 
 
} 
 
echo $format = '{ 
 
    "cols":[ 
 
     {"label":"date1","pattern":"","type":"string"}, 
 
     {"label":"count","pattern":"","type":"number"} 
 
    ], 
 
    "rows":' . json_encode($rows) . '}';

にアクセスできないため、SQLクエリが空であることを述べています

Answer 1

その他の条件がありません。 $時間チェック条件を追加しますが、else部分を追加する必要があります。 statemetns場合で

session_start(); 
    $data_set=$_SESSION['config']; 
    include("inc/users/$data_set.php"); 
    include('database.php'); 
    $connection=new database(); 
    $con2=$connection->connect($db,$user,$pass,$host); 
    $time= $_POST['tar']; 

    if(!empty($time)){ 
     if($time=='week') { 
      $sql="SELECT COUNT(DISTINCT `username`) AS `count`,date(`AcctStartTime`) AS `date1` FROM `radacct` where date(AcctStartTime) = curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY AND date(AcctStartTime) < curdate() - INTERVAL DAYOFWEEK(curdate())-1 DAY"; 
     } else if($time=='month') { 
      $sql="SELECT COUNT(DISTINCT `username`) AS `count`,date(`AcctStartTime`) AS `date1` FROM radacct WHERE YEAR(AcctStartTime) = YEAR(CURRENT_DATE - INTERVAL 1 MONTH) AND MONTH(AcctStartTime) = MONTH(CURRENT_DATE - INTERVAL 1 MONTH)"; 
     } else if($time=='year') {  
      $sql="SELECT COUNT(DISTINCT `username`) AS `count`,date(`AcctStartTime`) AS `date1` FROM radacct WHERE YEAR(AcctStartTime) = YEAR(CURRENT_DATE - INTERVAL 1 YEAR)"; 
     } 
    } else { 
     //you have to write default query here 
     $result = $con2->query($sql);  
     while($result2= $result->fetch_assoc()) { 
     $rows[]=array("c"=>array("0"=>array("v"=>$result2['date1'],"f"=>NULL),"1"=>array("v"=>(int)$result2['count'],"f" =>NULL))); 
    } 

    echo $format = '{ 
    "cols":[ 
     {"label":"date1","pattern":"","type":"string"}, 
     {"label":"count","pattern":"","type":"number"} 
    ], 
    "rows":'.json_encode($rows).'}'; 

Answer 2

$sqlが空の場合は、$timeが空であることを意味します。あなたは値が何であるかをチェックしようとしましたか？ $time=$_POST['tar'];は、フォームからnullを返している可能性があります。