このアクセスコードをsqliteコードに書く方法

Question

SELECT Person.Person_id、Person.name、Person.last_name、（debt.person_id = Person.Person_idの負債からselect sum（debt.paye））AS sum_pay、（select sum負債からの債務.not_paye）credit.person_id = Person.Person_id AS sum_not_pay、[sum_pay] - [sum_non_pay] AS def FROM Person;

Answer 1

select Person.Person_id, Person.name, Person.last_name,sum_pay,sum_non_pay, sum_pay-sum_non_pay as def 
from 
(
SELECT Person.Person_id, Person.name, Person.last_name, (select sum(credit.paye) from credit where credit.person_id= Person.Person_id) AS sum_pay, (select sum(credit.non_paye) from credit where credit.person_id= Person.Person_id) AS sum_non_pay 
from person 
)