配列とオブジェクトを操作する

Question

これは私が苦労している問題であるので、私はそれをうまく説明できないかもしれません！

私は値の配列と2つの文字列を持っています：

["5", "6"] 
"DEPOT_NAME", 
"DEPOT_ID" 

私も（この例では一つだけが、複数の可能）オブジェクトの配列を持っている：

私は私がいることを DEPOT_NAMEキーの値を取得する必要が持っている値を使用して

[ 
{ 
    columns: [ 
    {name: "DEPOT_ID"}, 
    {name: "DEPOT_NAME"}, 
    {name; "REGION_ID"}, 
    {name: "CREATED_DATE"}, 
    {name: "MODIFIED_DATE"} 
    ], 
    id: 1, 
    rows: [ 
    {data: {DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}} 
    ], 
    title: "Depots" 
} 
] 

正しいDEPOT_IDの値に相当します。上記の配列を使用して、私が想定している正しいデポIDを見つけることができますが、どのようにデポ名の値を取得するのですか？

私はそれを説明したかったと思います。あなたがもっと明確にする必要があれば、私はそれをもっと明確にするように努力します。

これについてのお手伝いがあれば幸いです。

お時間をいただきありがとうございます。

Answer 1

あなたがオブジェクトを反復したかっをフィルタリングすることができ目標値のみを取得します。

function getValues(key, values, target) { 
 
    return data[0].rows. 
 
     filter(a => values.indexOf(a.data[key]) !== -1). 
 
     map(a => a.data[target]); 
 
} 
 

 
var data = [{ columns: [{ name: "DEPOT_ID" }, { name: "DEPOT_NAME" }, { name: "REGION_ID" }, { name: "CREATED_DATE" }, { name: "MODIFIED_DATE" }], id: 1, rows: [{ data: { DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }], title: "Depots" }]; 
 

 
console.log(getValues("DEPOT_ID", ["5", "6"], "DEPOT_NAME"));

function getValues(key, values, target) { 
 
    return data[0].rows.filter(function (a) { 
 
     return values.indexOf(a.data[key]) !== -1; 
 
    }).map(function (a) { return a.data[target]; }); 
 
} 
 

 
var data = [{ columns: [{ name: "DEPOT_ID" }, { name: "DEPOT_NAME" }, { name: "REGION_ID" }, { name: "CREATED_DATE" }, { name: "MODIFIED_DATE" }], id: 1, rows: [{ data: { DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }, { data: { DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03" } }], title: "Depots" }]; 
 

 
console.log(getValues("DEPOT_ID", ["5", "6"], "DEPOT_NAME"));

ES6

Answer 2

この例では、要素「ブリストル」および「クロイドン」でアレイを生成する（持つIDの配列に基づいて、[5、6]）：

// your example object 

var yourObj = [ 
{ 
    columns: [ 
    {name: "DEPOT_ID"}, 
    {name: "DEPOT_NAME"}, 
    {name: "REGION_ID"}, 
    {name: "CREATED_DATE"}, 
    {name: "MODIFIED_DATE"} 
    ], 
    id: 1, 
    rows: [ 
    {data: {DEPOT_ID: "0", DEPOT_NAME: "London", REGION_ID: "0", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "1", DEPOT_NAME: "Abbey Road", REGION_ID: "1", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "3", DEPOT_NAME: "Romford", REGION_ID: "3", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "5", DEPOT_NAME: "Bristol", REGION_ID: "5", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}}, 
    {data: {DEPOT_ID: "6", DEPOT_NAME: "Croydon", REGION_ID: "6", CREATED_DATE: "2016-05-03", MODIFIED_DATE: "2016-05-03"}} 
    ], 
    title: "Depots" 
} 
]; 

// example code to fetch the depot names based on ids 

var ids = [5, 6]; 
var depotNames = []; 
for(var i = 0; i<yourObj.length; i++){ 
    var rows = yourObj[i].rows; 
    for(var j =0; j < rows.length; j++){ 
    for(id in ids){ 
     if(rows[j].data.DEPOT_ID == ids[id]){ 
      depotNames.push(rows[j].data.DEPOT_NAME); 
     } 
    } 

    } 
} 

Answer 3

function fetchData(cols, ids, mainArray) { 
    var data = []; 
    for(var i=0;i < mainArray.length; i++) { 
     for(var c =0;c<mainArray[i].rows.length;c++) { 

     for(var id in ids) { 
      if(mainArray[i].rows[c].data.DEPOT_ID == ids[id]) { 
       var temp = {}; 
       for(col in cols) { 
        temp[cols[col]] = mainArray[i].rows[c].data[cols[col]]; 
       }   
       data.push(temp); 
      } 
     } 
     } 
    } 

    return data; 
} 

使用法：なFetchData（[ "DEPOT_NAME"、 "DEPOT_ID"]、[ "5"、 " 6 "]、YourArray）;