Pythonのリスト、私はリストを含む辞書のリストを持っている

Question

を理解：

a = [{'alpha': 'a', 'val': 10, 'num': ['one', 'two']}, 
    {'alpha': 'b', 'val': 22, 'num': ['two']}, 
    {'alpha': 'c', 'val': 1, 'num': ['seven']}, 
    {'alpha': 'a', 'val': 10, 'num': ['three','nine']}, 
    {'alpha': 'b', 'val': 9, 'num': ['two', 'four']}] 

私が欲しいの出力は次のようになります。

[{'alpha': 'a', 'TotalVal': 20, num: ['one', 'two', 'three', 'nine'], 'numlen': 4}, 
{'alpha': 'b', 'TotalVal': 31, num: ['two', 'four'], 'numlen': 2}, 
{'alpha': 'c', 'val': 1, 'num': ['seven'], 'numlen': 1}] 

私は次のことを試してみました：

sumVal = collections.defaultdict(float) 
for info in a: 
    sumVal[info['alpha']] += info['val'] 

sumVal = [{'alpha': c, 'TotalVal': sumVal[c]} for c in sumVal] 

numList = collections.defaultdict(list) 
for info in a: 
    numList[info['alpha']].append(info['num']) 
numList = [{'alpha': k, 'num': set(v), 'len': len(set(v))} for k, v in numList.items()] 

def merge_lists(l1, l2, key): 
    merged = {} 
    for item in l1+l2: 
     if item[key] in merged: 
      merged[item[key]].update(item) 
     else: 
      merged[item[key]] = item 
    return [val for (_, val) in merged.items()] 

final = merge_lists(sumVal, numList, 'alpha') 

numListの出力が得られません。次のエラーを取得します。

TypeError: unhashable type: 'list'

希望の出力をより少ないステップで取得してエラーを取り除くにはどうすればよいですか？

Answer 1

このコードを試してみてください。問題はこのラインである

a = [{'alpha':'a','val':10,'num':['one','two']},{'alpha':'b','val':22,'num':['two']},{'alpha':'c','val':1,'num':['seven']},{'alpha':'a','val':10,'num':['three','nine']},{'alpha':'b','val':9,'num':['two','four']}] 

def merge_dicts(x, y): 
    x.update(y) 
    return x 

def r(acc, x): 
    if x['alpha'] in acc: 
     acc[x['alpha']]['TotalVal'] += x['val'] 
     acc[x['alpha']]['num'] |= set(x['num']) 
     acc[x['alpha']]['numlen'] = len(acc[x['alpha']]['num']) 
    else: 
     acc[x['alpha']] = { 
      'TotalVal': x['val'], 
      'num': set(x['num']), 
      'numlen': len(set(x['num'])), 
     } 
    return acc 

result = map(lambda (x, y): merge_dicts({'alpha': x}, y), 
      reduce(r, a, {}).iteritems()) 
print(result) 

Answer 2

：

numList[info['alpha']].append(info['num']) 

リストにリストを追加するには、あなたがに追加されているリスト内で追加されているリストを置きます。

あなたが望むものは伸びていると思います。

append vs. extend

Answer 3

#!/usr/bin/env python 

a = [{'alpha':'a','val':10,'num':['one','two', 'one', 'two']},{'alpha':'b','val':22,'num':['two']},{'alpha':'c','val':1,'num':['seven']},{'alpha':'a','val':10,'num':['three','nine']},{'alpha':'b','val':9,'num':['two','four']}] 


def merge_lists(src, key): 
    merged = {} 
    for i in src: 
     _key = i[key] 
     if _key in merged: 
      merged[_key]['TotalVal'] += i['val'] 
      merged[_key]['num'].extend(i['num']) 
      merged[_key]['num'] = list(set(i['num'])) 
      merged[_key]['numlen'] = len(merged[_key]['num']) 
     else: 
      merged[_key] = {'TotalVal': i['val'], 'alpha': i['alpha'], 'num': i['num'], 'numlen': 1} 

    return [val for (_, val) in merged.items()] 


final = merge_lists(a, 'alpha') 

print(final) 

出力： [{ 'α'： 'A'、 'TotalVal'：20 'NUM'：[ '9'、 '3']、 'numlen'：2 1、 'num'：['seven']、 'numlen'：1}、{'alpha'： 'b'、 'TotalVal'：31、 '}'、{'アルファ'： 'c' NUM '：[' 4」、 '2']、 '' numlen：2}]

Answer 4

などの他の回答として短いが単純ではなく、その実装に

a = [{'alpha':'a','val':10,'num':['one','two']}, 
    {'alpha':'b','val':22,'num':['two']}, 
    {'alpha':'c','val':1,'num':['seven']}, 
    {'alpha':'a','val':10,'num':['three','nine']}, 
    {'alpha':'b','val':9,'num':['two','four']}] 

new_list = [] 

# Loop through entries 
for entry in a: 
    # Store first entries 
    if entry['alpha'] not in [i['alpha'] for i in new_list]: 
     new_dict = {'alpha': entry['alpha'], 
        'TotalVal': entry['val'], 
        'num': entry['num'], 
        'numlen': len(entry['num'])} 
     new_list.append(new_dict) 
     continue 

    # Add in additional entries 
    for i, n in enumerate(new_list): 
     if n['alpha'] == entry['alpha']: 
      entry_vals = entry.values() 
      new_list[i]['TotalVal'] = new_list[i]['TotalVal'] + entry['val'] 
      new_list[i]['num'] = new_list[i]['num'] + entry['num'] 
      new_list[i]['numlen'] = len(new_list[i]['num']) 

# filter final data 
for i, n in enumerate(new_list): 
    # Remove duplicate entries in num 
    for entry in n['num']: 
     if n['num'].count(entry) > 1: 
      new_list[i]['num'].remove(entry) 

    # Update numlen 
    new_list[i]['numlen'] = len(new_list[i]['num']) 

print new_list 

Answer 5

a = [{'alpha':'a','val':10,'num':['one','two']}, 
    {'alpha':'b','val':22,'num':['two']}, 
    {'alpha':'c','val':1,'num':['seven']}, 
    {'alpha':'a','val':10,'num':['three','nine']}, 
    {'alpha':'b','val':9,'num':['two','four']}] 

a2 = [] 
alphas = set(d['alpha'] for d in a) 
for alpha in alphas: 
    TotalVal, num, numlen = 0, set(), 0 
    for d in a: 
     if d['alpha'] == alpha: 
      TotalVal += d['val'] 
      num = num | set(d['num']) 
      numlen += 1 
    new_dict = {'alpha': alpha, 'num': list(num), 'numlen': numlen} 
    if numlen > 1: 
     new_dict['TotalVal'] = TotalVal 
    else: 
     new_dict['val'] = TotalVal 
    a2.append(new_dict) 

デモ：

>>> for d in a2: print(d) 
{'alpha': 'a', 'num': ['three', 'nine', 'two', 'one'], 'numlen': 2, 'TotalVal': 20} 
{'alpha': 'c', 'num': ['seven'], 'numlen': 1, 'val': 1} 
{'alpha': 'b', 'num': ['four', 'two'], 'numlen': 2, 'TotalVal': 31}