Pythonの特殊文字に基づいてサブリストに動的リストを分割

Question

私は長い間解決策を見つけようとしているPythonの基本的な質問が1つありますが、正しい出力が得られません。

textvalues=[['1 of 2 DOCUMENTS', 'The New York Times', 'March 17, 2016 Thursday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section A; Column 0; Classified; Pg. 19', 'LENGTH: 176 words', 'LOAD-DATE: March 17, 2016', 'Copyright 2016 The New York Times Company', '', '2 of 2 DOCUMENTS', 'The New York Times', 'March 16, 2016 Wednesday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section B; Column 0; Classified; Pg. 16', 'LENGTH: 176 words', 'LOAD-DATE: March 16, 2016', 'Copyright 2016 The New York Times Company']] 

ここで私は上記のリストを「特殊文字」に基づくサブリストに分割する必要があります。上記のリストはサンプルリストであり、メインリストは動的であり、リストの長さが異なる場合があります。いずれにしても、リストは ""文字で区切る必要があります。私が試してみました

ソリューション：

MainText = str(textvalues) 
split_index = MainText.index('',) 
l2 = MainText[:split_index] 
print(l2) 

予想される解決策：

[['1 of 2 DOCUMENTS', 'The New York Times', 'March 17, 2016 Thursday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section A; Column 0; Classified; Pg. 19', 'LENGTH: 176 words', 'LOAD-DATE: March 17, 2016', 'Copyright 2016 The New York Times Company'] ,['2 of 2 DOCUMENTS', 'The New York Times', 'March 16, 2016 Wednesday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section B; Column 0; Classified; Pg. 16', 'LENGTH: 176 words', 'LOAD-DATE: March 16, 2016', 'Copyright 2016 The New York Times Company']] 

は、問題を解決するために私を助けてください。おかげ

Answer 1

import itertools 

textvalues=[['1 of 2 DOCUMENTS', 'The New York Times', 'March 17, 2016 Thursday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section A; Column 0; Classified; Pg. 19', 'LENGTH: 176 words', 'LOAD-DATE: March 17, 2016', 'Copyright 2016 The New York Times Company', '', '2 of 2 DOCUMENTS', 'The New York Times', 'March 16, 2016 Wednesday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section B; Column 0; Classified; Pg. 16', 'LENGTH: 176 words', 'LOAD-DATE: March 16, 2016', 'Copyright 2016 The New York Times Company']] 
groups = [] 
for a,b in itertools.groupby(textvalues[0], lambda x: x is not ''): 
    if a: 
     groups.append(list(b)) 
print groups 

は出力：

[['1 of 2 DOCUMENTS', 'The New York Times', 'March 17, 2016 Thursday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section A; Column 0; Classified; Pg. 19', 'LENGTH: 176 words', 'LOAD-DATE: March 17, 2016', 'Copyright 2016 The New York Times Company'], ['2 of 2 DOCUMENTS', 'The New York Times', 'March 16, 2016 Wednesday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section B; Column 0; Classified; Pg. 16', 'LENGTH: 176 words', 'LOAD-DATE: March 16, 2016', 'Copyright 2016 The New York Times Company']] 

Answer 2

基本的に、あなたがコンテンツをループ、バッファ内の部分文字列を格納することができ、かつ''セパレータを渡って来たときにメインリストにバッファをダンプ：

result = list() 
line = list() 
for element in textvalues[0]: 
    if element != '': 
     line.append(element) 
    else: 
     result.append(line) 
     line = list() 

Answer 3

textvalues=[['1 of 2 DOCUMENTS', 'The New York Times', 'March 17, 2016 Thursday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section A; Column 0; Classified; Pg. 19', 'LENGTH: 176 words', 'LOAD-DATE: March 17, 2016', 'Copyright 2016 The New York Times Company', '', '2 of 2 DOCUMENTS', 'The New York Times', 'March 16, 2016 Wednesday\xa0\xa0Late Edition - Final', 'Paid Notice: Deaths THORNTON, ROBERT', 'SECTION: Section B; Column 0; Classified; Pg. 16', 'LENGTH: 176 words', 'LOAD-DATE: March 16, 2016', 'Copyright 2016 The New York Times Company']] 

textvalues2 = [] 

for i in ','.join(i for i in textvalues[0]).split(',,') : 
    textvalues2.append(i.split(','))