5
入力を受け取り、多数のフィルタで処理し、最後に出力を得るために、フィルタ/パイプラインパターンを実装しようとしています。入力/出力タイプがフィルタごとに異なる汎用パイプライン
入力タイプと最終出力タイプが同じで、各フィルタも同じタイプを使用している場合は、これを簡単に実行できます。しかし、私は1つのタイプを入力し、別のタイプを取得したい。
ファイル名でcsvfileを取得し、個々の文字列に読み込んで解析し、検証してxmlとして出力します。擬似コードの例：
input = filename
filter = load csv file <filename, list<string>>
filter = parse csv <list<string>, list<businessobject>>
filter = validate objects <list<businessobject>, list<businessobject>> *... return type same as input type in this case.*
filter = create xml <list<businessobject>, XDocument>
filter = validate XDoc <XDocument, XDocument>
output = XDocument
ここでは、私がこれまで持っているものです。
IFilter, FilterBase, FilterImplementation
IPipeline, Pipeline
IBusinessObject, BusinessObject, BusinessObjectImplementation
私の意図は、しかし、私は「Aを取得T and U are IBusinessObject
IFilter<T,U>のリストを持ってできるようにしましたIFilter<IBusinessObject, IBusinessObject>をリストに追加しようとすると、BusinessObjectImplementationからIBusinessObjectに変換できません。
public interface IFilter<T, U>
where T : IBusinessObject
where U : IBusinessObject
{
U Execute(T input);
}
public abstract class FilterBase<T, U> : IFilter<T, U>
where T : IBusinessObject
where U : IBusinessObject, new()
{
protected abstract U Process(T input);
public U Execute(T input)
{
return Process(input);
}
}
public class FilterCsvFileLoader<T, U> : FilterBase<T, U>, IFilter<T, U>
where T : FilenameObject, IBusinessObject
where U : CSVFile, IBusinessObject, new()
{
public FilterCsvFileLoader()
{ }
protected override U Process(T input)
{
U result = new CSVFile(input) as U;
return result;
}
}
public interface IPipeline
{
IBusinessObject Execute(IBusinessObject input);
IPipeline Register(IFilter<IBusinessObject, IBusinessObject> filter);
}
public class Pipeline : IPipeline
{
private List<IFilter<IBusinessObject, IBusinessObject>> _filters = new List<IFilter<IBusinessObject, IBusinessObject>>();
public IBusinessObject Execute(IBusinessObject input)
{
var result = input;
foreach (var filter in _filters)
{
result = filter.Execute(result);
}
return result;
}
public IPipeline Register(IFilter<IBusinessObject, IBusinessObject> filter)
{
_filters.Add(filter);
return this;
}
}
public interface IBusinessObject
{
bool Validate();
List<string> ValidationErrors { get; }
}
public class BusinessObject : IBusinessObject
{
private List<BusinessRule> _businessRules = new List<BusinessRule>();
private List<string> _validationErrors = new List<string>();
public List<string> ValidationErrors
{
get { return _validationErrors; }
}
protected void AddRule(BusinessRule rule)
{
_businessRules.Add(rule);
}
public bool Validate()
{
bool isValid = true;
_validationErrors.Clear();
foreach (BusinessRule rule in _businessRules)
{
if (!rule.Validate(this))
{
isValid = false;
_validationErrors.Add(rule.ErrorMessage);
}
}
return isValid;
}
}
public class FilenameObject : BusinessObject, IBusinessObject
{
string _filename;
public string Filename
{
get { return _filename; }
}
public FilenameObject(string filename)
{
_filename = filename;
}
}
public class CSVFile : BusinessObject, IBusinessObject
{
private string _filename;
private string[] _splitChar = new string[] { "," };
public List<List<string>> Lines { get; set; }
public CSVFile()
{ }
public CSVFile(FilenameObject filename)
: this()
{
_filename = filename.Filename;
Lines = new List<List<string>>();
}
private void ImportFile()
{
FileInfo fi = new FileInfo(_filename);
using (StreamReader sr = new StreamReader(fi.Open(FileMode.Open, FileAccess.Read, FileShare.None)))
{
String readline;
while ((readline = sr.ReadLine()) != null)
{
var line = (from l in readline.Split(_splitChar, StringSplitOptions.None)
select l.Trim()).ToList();
Lines.Add(line);
}
}
}
}
class Program
{
static void Main(string[] args)
{
var pipeline = new Pipeline()
.Register(new FilterCsvFileLoader<FilenameObject, CSVFile>());
}
}
Apols 0
例外が
エラー2引数1以上.Registerラインである： '
はBusinessLogic.FilterCsvFileLoader<BusinessObjects.FilenameObject,BusinessObjects.CSVFile>' から変換することはできません
'BusinessLogic.IFilter<BusinessObjects.IBusinessObject,BusinessObjects.IBusinessObject>' へ C：ビジュアル\ davidc \ドキュメント\ \ユーザープロジェクト\ MPMeFeed \ TestConsole \ Program.csを\ Studio 2010の 15 23 TestConsole
ありがとうございました、これは動作しませんでした理由として良い説明。 – BlueChippy