オブジェクトの配列が同じ値を持っているかどうかを確認するにはどうすればいいですか

Question

私の配列には同じアドレスのIDが含まれていますが、phoneTypeとphonenumberは異なります。 配列を反復処理するためにいくつかの助けが必要です。私は、adressidが同じ場合にphoneTypeとphonenumberを取得したいと思います。配列内のオブジェクトの値を比較すると、私は立ち往生し続けます。

var userdetail = [ 
    { name: "Steve", adressID: "1", phoneType:"main", phonenumber:"12222228"}, 
    { name: "Steve", adressID: "1", phoneType:"fax" , phonenumber:"55555668"}, 
    { name: "Peter", adressID: "2", phoneType:"main", phonenumber:"67544442"}, 
    { name: "Elaine", adressID: "3", phoneType:"main", phonenumber:"87877778"}, 
    { name: "Elaine", adressID: "3", phoneType:"mobile",phonenumber:"23234678"}, 
    { name: "Steve", adressID: "1", phoneType:"work", phonenumber:"42222228"}, 
]; 

私、その後、あなたが好きな名前のアクセスをhereを参照し、まず、ここで

 { 
    "name": "Steve", 
    "adressID": "1", 
    "phoneType": "main", 
    "phonenumber": "12222228" 
}, 
{ 
    "name": "Steve", 
    "adressID": "1", 
    "phoneType": "fax", 
    "phonenumber": "55555668" 
}, 
{ 
    "name": "Steve", 
    "adressID": "1", 
    "phoneType": "work", 
    "phonenumber": "42222228" 
} 

Answer 1

あるAddressId

var userdetail = [{ 
 
    name: "Steve", 
 
    adressID: "1", 
 
    phoneType: "main", 
 
    phonenumber: "12222228" 
 
    }, 
 
    { 
 
    name: "Steve", 
 
    adressID: "1", 
 
    phoneType: "fax", 
 
    phonenumber: "55555668" 
 
    }, 
 
    { 
 
    name: "Peter", 
 
    adressID: "2", 
 
    phoneType: "main", 
 
    phonenumber: "67544442" 
 
    }, 
 
    { 
 
    name: "Elaine", 
 
    adressID: "3", 
 
    phoneType: "main", 
 
    phonenumber: "87877778" 
 
    }, 
 
    { 
 
    name: "Elaine", 
 
    adressID: "3", 
 
    phoneType: "mobile", 
 
    phonenumber: "23234678" 
 
    }, 
 
    { 
 
    name: "Steve", 
 
    adressID: "1", 
 
    phoneType: "work", 
 
    phonenumber: "42222228" 
 
    }, 
 
]; 
 
var result = userdetail.reduce(function(res, o) { 
 
    res[o.adressID] || (res[o.adressID] = []); // if the adressID key doesn't exist, set it to be an array 
 

 
    res[o.adressID].push(o); // push the object into the array 
 

 
    return res; 
 
}, {}); 
 
console.log(result)

としてこの同じキーを持つオブジェクトの配列であろうあるAddressIdキーと、このキーの値となるオブジェクトを作成

Answer 2

それを行うための一つの方法であること、機能がSO答えるから撮影されたアレイをGROUPBYすべきアウト期待、以下のスニペットを参照してください！

var userdetail = [{ 
 
    name: "Steve", 
 
    adressID: "1", 
 
    phoneType: "main", 
 
    phonenumber: "12222228" 
 
    }, 
 
    { 
 
    name: "Steve", 
 
    adressID: "1", 
 
    phoneType: "fax", 
 
    phonenumber: "55555668" 
 
    }, 
 
    { 
 
    name: "Peter", 
 
    adressID: "2", 
 
    phoneType: "main", 
 
    phonenumber: "67544442" 
 
    }, 
 
    { 
 
    name: "Elaine", 
 
    adressID: "3", 
 
    phoneType: "main", 
 
    phonenumber: "87877778" 
 
    }, 
 
    { 
 
    name: "Elaine", 
 
    adressID: "3", 
 
    phoneType: "mobile", 
 
    phonenumber: "23234678" 
 
    }, 
 
    { 
 
    name: "Steve", 
 
    adressID: "1", 
 
    phoneType: "work", 
 
    phonenumber: "42222228" 
 
    }, 
 
]; 
 

 
var groupBy = function(xs, key) { 
 
    return xs.reduce(function(rv, x) { 
 
    (rv[x[key]] = rv[x[key]] || []).push(x); 
 
    return rv; 
 
    }, {}); 
 
}; 
 

 
var data = groupBy(userdetail, 'name'); 
 
console.log(data); 
 

 
//access values for steve 
 
for (var k of data['Steve']) { 
 
    console.log(k['phonenumber']); 
 
    console.log(k['phoneType']); 
 
}

.as-console { 
 
    height: 100%; 
 
} 
 

 
.as-console-wrapper { 
 
    max-height: 100% !important; 
 
    top: 0; 
 
}

Answer 3

私はこのようなもののためにLodashを好むデータ争い）...

var results = _.filter(userdetail, {name: 'Steve'});