複数の行が挿入されていない状態で挿入する

Question

この挿入物を使用することはできません。誰かが私が間違っていることを教えてくれますか？

$id_application = 1; 
foreach ($array_account as $rows) { 
    $e_mail = $rows["EMAIL"]; 
    $pwd = $rows["PWD"]; 
    $salt = $rows["SALT"]; 

    $values = "(" . $e_mail . ", " .$pwd . ", " .$salt . ", " . $id_application . ")"; 
    $query = "INSERT INTO DBNAME..ACCOUNT (EMAIL, PWD, SALT, ID_APPLICATION) " 
    . " VALUES " . $values; 
    $result = sybase_query($query);  
} 

これらはigetがエラーです：

Column names are illegal. (severity 15, procedure N/A 
The identifier that starts with '...' is too long. Maximum length is 30 
The name '...' is illegal in this context. Only constants, constant expressions, or variables 
allowed here 

私のような中央SYBASE内の単一の行を挿入することができるよ：

insert into DBNAME..ACCOUNT (EMAIL, PWD, SALT, ID_APPLICATION) 
select EMAIL, PWD, SALT, 3 from ACCOUNT where ID = 10 go 

Answer 1

Do this $values = "('" . $e_mail . "', '" .$pwd . "', '" .$salt . "', '" . $id_application . "')";