PHP pdoを使用してJSONネストされたオブジェクトを作成する方法

Question

ここで私はほとんどの関連する回答をstackoverflowで調べましたが、私の場合に適したものを見つけることができませんでした。

どんな種類の返信も高く評価されます。私は

news_id

comment_namesをコメントをという名前の2つのMySQLテーブルからデータを取得し、comment_id

• コメントテーブルの下の値でcomments_replyするPHP PDOを使用しています

• COMMENT_DATE

comment_replyテーブル

• は
• をreply_id私が代わりにこのようなJOSNフォーマットされた結果、その結果として戻って空の配列を取得し、返信
• REPLY_DATE

reply_names

をcomment_id：

[ 
    {"id": 1, 
    "comment_date": "2017-08-09", 
    "comment_time": "06:10:00", 
    "names": "Imenwo Alex", 
    "img": "c1.jpg", 
    "comments": "<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>", 
    "replies":[ 
     { 
       "id": 1, 
       "reply_date": "2017-08-09", 
       "reply_time": "06:10:00", 
       "names": "frank Alex", 
       "img": "c1.jpg", 
       "reply": "<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>" 
      }, 
      { 
       "id": 2, 
       "reply_date": "2017-08-09", 
       "reply_time": "06:10:00", 
       "names": "frank Alex", 
       "img": "c1.jpg", 
       "reply": "<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>" 
      } 
    ] 
    }, 
    {"id": 2, 
    "comment_date": "2017-08-09", 
    "comment_time": "06:10:00", 
    "names": "Imenwo Alex", 
    "img": "c1.jpg", 
    "comments": "<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>", 
    "replies":[ 
      { 
       "id": 1, 
       "reply_date": "2017-08-09", 
       "reply_time": "06:10:00", 
       "names": "frank Alex", 
       "img": "c1.jpg", 
       "reply": "<p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p><p>Lorem ipsum dolor sit amet, consectetur adipisicing elit,There are many variations of passages of Lorem Ipsum available, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>" 
      } 
     ] 
    } 
] 

以下は

私のPHPスクリプトです：

// 
     $q = "SELECT * FROM comments WHERE comments.news_id =:id";   
     //prepare 
     $stmt = $this->DB_con->prepare($q); 
     //bind parameters 
     $stmt->bindParam(':id', $id); 

     //create an array 
     $json_response = array(); 
     while($obj=$stmt->fetch(PDO::FETCH_OBJ)) { 

      $currentComments = array(
       'id' => $obj->comment_id, 
       'comment_names' => $obj->comment_names, 
       'comment_date' => $obj->comment_date, 
       'comment_time' => $obj->comment_time, 
       'comment_img' => $obj->comment_img, 
       'comments' => $obj->comments, 
       'replies' => array() 
     ); 

      // 
      $r = "SELECT * FROM comments_reply WHERE comments_reply.comment_id =:id"; 
      //prepare 
      $stmt = $this->DB_con->prepare($r); 
      //bind parameters 
      $stmt->bindParam(':id', $obj->comment_id); 
      while($obj=$stmt->fetch(PDO::FETCH_OBJ)) { 

       $currentComments['replies'][] = array(
        'id' => $obj->reply_id, 
        'reply_names' => $obj->reply_names, 
        'reply_date' => $obj->reply_date, 
        'reply_time' => $obj->reply_time, 
        'reply_img' => $obj->reply_img, 
        'reply' => $obj->reply 
      ); 

      } 
      array_push($json_response, $currentComments); //push the values in the array 

     } 
     return json_encode($json_response); 

Answer 1

$ stmtはと$ OBJを上書きしないでください。このような何か：

 $q = "SELECT * FROM comments WHERE comments.news_id =:id";   
     //prepare 
     $stmt = $this->DB_con->prepare($q); 

     $r = "SELECT * FROM comments_reply WHERE comments_reply.comment_id =:id"; 
     //prepare 
     $stmt2 = $this->DB_con->prepare($r); 

     //execute with bound parameter 
     $stmt->execute(array(':id'=> $id)); 

     //create an array 
     $json_response = array(); 

     while($obj=$stmt->fetch(PDO::FETCH_OBJ)) { 

      $currentComments = array(
       'id' => $obj->comment_id, 
       'comment_names' => $obj->comment_names, 
       'comment_date' => $obj->comment_date, 
       'comment_time' => $obj->comment_time, 
       'comment_img' => $obj->comment_img, 
       'comments' => $obj->comments, 
       'replies' => array() 
     ); 

      // 
      $stmt2->execute(array(':id'=> $obj->comment_id)); 

      while($obj2=$stmt2->fetch(PDO::FETCH_OBJ)) { 

       $currentComments['replies'][] = array(
        'id' => $obj2->reply_id, 
        'reply_names' => $obj2->reply_names, 
        'reply_date' => $obj2->reply_date, 
        'reply_time' => $obj2->reply_time, 
        'reply_img' => $obj2->reply_img, 
        'reply' => $obj2->reply 
      ); 

      } 
      array_push($json_response, $currentComments); //push the values in the array 

     } 
     return json_encode($json_response);