各反復で値を取得してリストに戻す方法

Question

私は人のリストを持っており、その年にプロパティの日付がある年にグループ化された人の数を取得したいと思います。 問題は、検索したい年数が現在の過去から現在までのものであることです。ユーザーがそれを選択することを願っています。 現在、私は10年前の情報を取得していますが、ユーザーは任意の年数を入力することができます。あなたは、列の最も簡単な解決策として、それはJSONとしてそれを持っていることをしたい場合は

select to_char(d, 'YYYY') as year, count(id) as total 
from 
    jb_persona 
    right join 
    generate_series(
     date_trunc('year', now() - interval '10 years'), 
     now(), interval '1 year' 
    ) gs(d) on gs.d = date_trunc('year', fecha_conversion) 
where id_iglesiafk = aidiglesia 
group by 1 

：：また、外側の出力でゼロカウント数年を持っている

CREATE OR REPLACE FUNCTION convertidos_neto_10_year_ago(IN aidiglesia integer) 

    RETURNS TABLE(cant0 bigint, cant1 bigint, cant2 bigint, cant3 bigint, cant4 bigint, cant5 bigint, cant6 bigint, cant7 bigint, cant8 bigint, cant9 bigint, cant10 bigint) AS 

$BODY$BEGIN 

RETURN Query SELECT 

(SELECT count(jb_persona.id) 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = date_part('year'::text, ('now'::text)::date) - (10)::double precision))) , 

(SELECT count(jb_persona.id) 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (9)::double precision)))) , 

(SELECT count(jb_persona.id) AS count3 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (8)::double precision)))) , 

(SELECT count(jb_persona.id) AS count4 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (7)::double precision)))) , 

(SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (6)::double precision)))) , 

(SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (5)::double precision)))) , 

(SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (4)::double precision)))) , 

    (SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (3)::double precision)))) , 

(SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (2)::double precision)))) , 

(SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (1)::double precision)))) , 

(SELECT count(jb_persona.id) AS count5 
      FROM jb_persona 
      WHERE ((jb_persona.id_iglesiafk = aidiglesia) AND (date_part('year'::text, jb_persona.fecha_conversion) = (date_part('year'::text, ('now'::text)::date) - (0)::double precision)))); 

END; 

$BODY$ 

    LANGUAGE plpgsql VOLATILE 
    COST 100 
    ROWS 1000; 

ALTER FUNCTION convertidos_neto_10_year_ago(integer) 

OWNER TO postgres; 

Answer 1

は、生成された年のシリーズに参加

select jsonb_object_agg(year, total) 
from (
    select to_char(d, 'YYYY') as year, count(id) as total 
    from 
     jb_persona 
     right join 
     generate_series(
      date_trunc('year', now() - interval '10 years'), 
      now(), interval '1 year' 
     ) gs(d) on gs.d = date_trunc('year', fecha_conversion) 
    where id_iglesiafk = aidiglesia 
    group by 1 
) s 

を9.4使用する場合

：

select jsonb_object(array_agg(year), array_agg(total::text)) 
from ...