を1つに式を統合し、単一のアレイ（パイソン）

Question

i = [2,3,4] 
interest = [1.08,1.0824,1.09,1.095] 

yr2 = (interest[0] * interest[1])**(1./i[0]) - 1. 
yr3 = (interest[0] * interest[1] * interest[2])**(1./i[1]) - 1. 
yr4 = (interest[0] * interest[1] * interest[2] * interest[3])**(1./i[2]) - 1. 

にそれを提示するために探して、私は2つの配列（上記）を宣言したが、私はこの形式で私の答えを表示するために探しています：

yield = [yr2,yr3,yr4] 

Answer 1

# data 
i = [2,3,4] 
interest = [1.08,1.0824,1.09,1.095] 

def count_interests(bar, interest): 
    """ 
    Returns a list: 
    [(interest[0] * interest[1]), (interest[0] * interest[1] * interest[2]), 
    (interest[0] * interest[1] * interest[2] * interest[3])] 
    """ 
    res = [] 
    compound = [interest[0]] 
    print(f'first compound {compound}') 
    for i in range(len(bar)): # [0,1,2] 
     inter = compound[i] * interest[i+1] 
     compound.append(inter) 
    print(compound) 
    return compound 

compound = count_interests(i, interest) 
compound.pop(0) 
print(compound) 
# [1.168992, 1.2742012800000002, 1.3952504016000002] 
zipped = zip(i, compound) 

def yr(zip): 
    res = [] 
    for k, v in zip: 
     temp = v ** (1./k) - 1 
     res.append(temp) 
    return res 

result = yr(zipped) 

1.、（関心[ -

結果

[0.0811993340730468, 0.08412496573593131, 0.08683355662001646]