Python-リストデータのnxnリストの半分を持つリストの対称リストを生成する

Question

私はこのリストのリストを持っており、それをリストの対称リストに変換したいと思います。私は何をすべきか？

[[0, 8, 4, 10, 12, 9, 15, 8, 11, 5, 9, 4, 10], 
    [0, 0, 7, 6, 8, 6, 7, 10, 12, 9, 8, 7, 5], 
    [0, 0, 0, 7, 9, 5, 8, 5, 4, 8, 6, 10, 8], 
    [0, 0, 0, 0, 6, 11, 5, 9, 8, 12, 11, 6, 9], 
    [0, 0, 0, 0, 0, 7, 9, 6, 9, 8, 4, 11, 10], 
    [0, 0, 0, 0, 0, 0, 10, 4, 3, 10, 6, 5, 7], 
    [0, 0, 0, 0, 0, 0, 0, 10, 9, 8, 5, 9, 10], 
    [0, 0, 0, 0, 0, 0, 0, 0, 11, 5, 9, 6, 7], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 9, 11, 11, 6], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6, 7, 5], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10, 7], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 9], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]] 

Answer 1

これは、あなたが「対称」によって何を意味するか、あなたがnumpyを使用して行うことができている場合は、次の

ベースのPythonを使用して

import numpy as np 

m = np.array([[0, 8, 4, 10, 12, 9, 15, 8, 11, 5, 9, 4, 10], 
    [0, 0, 7, 6, 8, 6, 7, 10, 12, 9, 8, 7, 5], 
    [0, 0, 0, 7, 9, 5, 8, 5, 4, 8, 6, 10, 8], 
    [0, 0, 0, 0, 6, 11, 5, 9, 8, 12, 11, 6, 9], 
    [0, 0, 0, 0, 0, 7, 9, 6, 9, 8, 4, 11, 10], 
    [0, 0, 0, 0, 0, 0, 10, 4, 3, 10, 6, 5, 7], 
    [0, 0, 0, 0, 0, 0, 0, 10, 9, 8, 5, 9, 10], 
    [0, 0, 0, 0, 0, 0, 0, 0, 11, 5, 9, 6, 7], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 9, 11, 11, 6], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6, 7, 5], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10, 7], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 9], 
    [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]) 

sym = m + m.transpose() 

sym.tolist() 

#  [[ 0, 8, 4, 10, 12, 9, 15, 8, 11, 5, 9, 4, 10], 
#  [ 8, 0, 7, 6, 8, 6, 7, 10, 12, 9, 8, 7, 5], 
#  [ 4, 7, 0, 7, 9, 5, 8, 5, 4, 8, 6, 10, 8], 
#  [10, 6, 7, 0, 6, 11, 5, 9, 8, 12, 11, 6, 9], 
#  [12, 8, 9, 6, 0, 7, 9, 6, 9, 8, 4, 11, 10], 
#  [ 9, 6, 5, 11, 7, 0, 10, 4, 3, 10, 6, 5, 7], 
#  [15, 7, 8, 5, 9, 10, 0, 10, 9, 8, 5, 9, 10], 
#  [ 8, 10, 5, 9, 6, 4, 10, 0, 11, 5, 9, 6, 7], 
#  [11, 12, 4, 8, 9, 3, 9, 11, 0, 9, 11, 11, 6], 
#  [ 5, 9, 8, 12, 8, 10, 8, 5, 9, 0, 6, 7, 5], 
#  [ 9, 8, 6, 11, 4, 6, 5, 9, 11, 6, 0, 10, 7], 
#  [ 4, 7, 10, 6, 11, 5, 9, 6, 11, 7, 10, 0, 9], 
#  [10, 5, 8, 9, 10, 7, 10, 7, 6, 5, 7, 9, 0]] 

Answer 2

あなたはこのようにそれを行うことができます。そして、

AT = [list(col) for col in zip(*A)] 

B = [r[:i]+s[i:] for i,(r,s) in enumerate(zip(AT,A))] 

：

>>> for r in B: print(r) 

[0, 8, 4, 10, 12, 9, 15, 8, 11, 5, 9, 4, 10] 
[8, 0, 7, 6, 8, 6, 7, 10, 12, 9, 8, 7, 5] 
[4, 7, 0, 7, 9, 5, 8, 5, 4, 8, 6, 10, 8] 
[10, 6, 7, 0, 6, 11, 5, 9, 8, 12, 11, 6, 9] 
[12, 8, 9, 6, 0, 7, 9, 6, 9, 8, 4, 11, 10] 
[9, 6, 5, 11, 7, 0, 10, 4, 3, 10, 6, 5, 7] 
[15, 7, 8, 5, 9, 10, 0, 10, 9, 8, 5, 9, 10] 
[8, 10, 5, 9, 6, 4, 10, 0, 11, 5, 9, 6, 7] 
[11, 12, 4, 8, 9, 3, 9, 11, 0, 9, 11, 11, 6] 
[5, 9, 8, 12, 8, 10, 8, 5, 9, 0, 6, 7, 5] 
[9, 8, 6, 11, 4, 6, 5, 9, 11, 6, 0, 10, 7] 
[4, 7, 10, 6, 11, 5, 9, 6, 11, 7, 10, 0, 9] 
[10, 5, 8, 9, 10, 7, 10, 7, 6, 5, 7, 9, 0] 

Answer 3

これは、サブリスト要素jサブリストが必要ですか？

x=[[0, 8, 4, 10, 12, 9, 15, 8, 11, 5, 9, 4, 10], 
[0, 0, 7, 6, 8, 6, 7, 10, 12, 9, 8, 7, 5], 
[0, 0, 0, 7, 9, 5, 8, 5, 4, 8, 6, 10, 8], 
[0, 0, 0, 0, 6, 11, 5, 9, 8, 12, 11, 6, 9], 
[0, 0, 0, 0, 0, 7, 9, 6, 9, 8, 4, 11, 10], 
[0, 0, 0, 0, 0, 0, 10, 4, 3, 10, 6, 5, 7], 
[0, 0, 0, 0, 0, 0, 0, 10, 9, 8, 5, 9, 10], 
[0, 0, 0, 0, 0, 0, 0, 0, 11, 5, 9, 6, 7], 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 9, 11, 11, 6], 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6, 7, 5], 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10, 7], 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 9], 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]] 

reversex = x[::-1] 
for l in reversex: 
    print (l) 

[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 9] 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 10, 7] 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 6, 7, 5] 
[0, 0, 0, 0, 0, 0, 0, 0, 0, 9, 11, 11, 6] 
[0, 0, 0, 0, 0, 0, 0, 0, 11, 5, 9, 6, 7] 
[0, 0, 0, 0, 0, 0, 0, 10, 9, 8, 5, 9, 10] 
[0, 0, 0, 0, 0, 0, 10, 4, 3, 10, 6, 5, 7] 
[0, 0, 0, 0, 0, 7, 9, 6, 9, 8, 4, 11, 10] 
[0, 0, 0, 0, 6, 11, 5, 9, 8, 12, 11, 6, 9] 
[0, 0, 0, 7, 9, 5, 8, 5, 4, 8, 6, 10, 8] 
[0, 0, 7, 6, 8, 6, 7, 10, 12, 9, 8, 7, 5] 
[0, 8, 4, 10, 12, 9, 15, 8, 11, 5, 9, 4, 10]