intに変換する際にJava文字列の生成エラーが発生しました

-1

Integer.parseInt（）を使用して、phonenumberを表す文字列を、私が使用できるintに変換しようとしています。intに変換する際にJava文字列の生成エラーが発生しました

これは私が取得していますエラーです：

Enter a 10-digit telephone number with optional space or dash after the first and the second block of three digits > 
5558759142 
Processing encrypted number "5558759142" 
Exception in thread "main" java.lang.NumberFormatException: For input string: "5558759142" 
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65) 
    at java.lang.Integer.parseInt(Integer.java:583) 
    at java.lang.Integer.parseInt(Integer.java:615) 
    at TelephoneNumberValidator.main(TelephoneNumberValidator.java:32) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) 
    at java.lang.reflect.Method.invoke(Method.java:498) 
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:147) 

Process finished with exit code 1

は、これは私のコードです：

import java.util.*; 
import java.lang.Integer; 

public class TelephoneNumberValidator { 
    public static void main(String[] args) { 
     final String VALID_PHONE_PATTERN = "[0-9]{3}[-| ]?[0-9]{3}[-| ]?[0-9]{4}"; 
     final int NUMBERS_FOLLOWING_AREA_CODE = 7; 
     final int DECRYPTED_AREA_CODE = 212; 
     Scanner scanKeyboard = new Scanner(System.in); 
     String userInput; 

     do { 
      System.out.println("Enter a 10-digit telephone number with optional space or dash after the first and the second block of three digits >"); 
      userInput = scanKeyboard.nextLine(); 
      //check to see if the phone number is correct 
      if (!userInput.matches(VALID_PHONE_PATTERN)) 
      { 
       System.out.println("The given input \" " + userInput + " \" is not valid"); 
      } 
     }while (!userInput.matches(VALID_PHONE_PATTERN)); 

     //extract int from string 
     String phoneJustNumbers = userInput; 
     phoneJustNumbers = phoneJustNumbers.replaceAll("-",""); // replaces hyphens 
     phoneJustNumbers = phoneJustNumbers.replaceAll(" ", ""); 

     System.out.println("Processing encrypted number \"" + phoneJustNumbers + "\""); 
     //check the first 3 digits (aka area code) to see if it matches 212 
     int areaCode = Integer.parseInt(phoneJustNumbers);//gets area code 
     int placeholderForAreaCode = 111; //set 111 so that each number in area code can be accounted for 
     int placeholderForEntirePhoneNum = 1111111111; //set each digit to 1 so we can shift later 
     for (int j = 0; j <= 9; j++) 
     { 
      if ((areaCode + (placeholderForAreaCode * j) == DECRYPTED_AREA_CODE)) // we are shifting each digit by one 
                         // to see if it matches the decrypted area code 
      { 
       System.out.println("The telephone number is \"" + (Integer.parseInt(phoneJustNumbers) * placeholderForEntirePhoneNum * j) 
         + "\" with a shift value of " + j); 
      } 
      else 
      { 
       System.out.println("The telephone number \"" + userInput + "\" cannot be decrypted area code."); 
      } 
     } 

    } 
}

私はハードコードされた文字列を代用しようとするので、それはInteger.parseIntを（使用して動作します）。これは私が私の弦を掃除する方法を信じて、何とかこれが働くのをやめてしまいます。私はjavaを初めて使っているので、それがなぜ、あるいは私が間違っていたのか分かりません。

出典

2017-03-05 Samier Mahagna