私はすべてのリンクhttp://example.com/1を解凍し、2 <br><br>
タグの後にすべてのリンクを無視したいと思います。ここ2タグの前に解析してくださいbeautifulsoup python
<div class="compost">
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index18" class="select_index"></span>text 2</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index19" class="select_index"></span>text 3</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index20" class="select_index"></span>text 4</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index21" class="select_index"></span>text 5</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index22" class="select_index"></span>text 6</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index23" class="select_index"></span>text 7</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index24" class="select_index"></span>text 8</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index25" class="select_index"></span>text 9</a></b>
<br>
<br>
<b><a target="_blank" href="http://example.com/2"><span id="s_index18" class="select_index"></span>text 2</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index19" class="select_index"></span>text 3</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index20" class="select_index"></span>text 4</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index21" class="select_index"></span>text 5</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index22" class="select_index"></span>text 6</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index23" class="select_index"></span>text 7</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index24" class="select_index"></span>text 8</a></b>
<br><b><a target="_blank" href="http://example.com/2"><span id="s_index25" class="select_index"></span>text 9</a></b>
<br>
<br>
<b><a target="_blank" href="http://example.com/3"><span id="s_index18" class="select_index"></span>text 2</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index19" class="select_index"></span>text 3</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index20" class="select_index"></span>text 4</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index21" class="select_index"></span>text 5</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index22" class="select_index"></span>text 6</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index23" class="select_index"></span>text 7</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index24" class="select_index"></span>text 8</a></b>
<br><b><a target="_blank" href="http://example.com/3"><span id="s_index25" class="select_index"></span>text 9</a></b>
<br>
<br>
私は解析する必要がある部分である:ここ
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index18" class="select_index"></span>text 2</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index19" class="select_index"></span>text 3</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index20" class="select_index"></span>text 4</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index21" class="select_index"></span>text 5</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index22" class="select_index"></span>text 6</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index23" class="select_index"></span>text 7</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index24" class="select_index"></span>text 8</a></b>
<br><b><a target="_blank" href="http://example.com/1"><span id="s_index25" class="select_index"></span>text 9</a></b>
は、すべてのリンクと私は知らない私のコード
for links in obja.find_all("div", class_="compost"):
if links.has_attr('href'):
print links['href']
#
aa = links.findAll('a')[0]
print aa.attrs['href']
txt = []
for i in links.findAll('br'):
txt.append(i.text)
print i.nextSibling
if i.nextSibling.text != u'br':
txt.append(i.nextSibling.text)
''.join(txt)
私のスクリプト抽出物の一部であり、どのように私はすべてhttp://example.com/1を抽出し、<br><br>
の後のすべてのリンクを無視することができますか?
あなただけの他のすべてのリンクを無視して、唯一の 'の' href'と 'A'タグをつかむことができますhttp://example.com/ 1? 'obja.find_all( 'a'、attrs = {'href': 'http://example.com/1'})' –
@GregReda、リンクは同じドメインを持つので、リダイレクトに使用できません。 – Kate