1
2つの列にヘッダーを展開した表があります。このテーブルに3Dグラフを描く方法、または精巧なヘッダーを持つテーブルにグラフを描画する方法は何でしょうか。2つの列に精巧なヘッダーでRを描画する
year
2014 2015 2016
Reported Detected Reported Detected Reported Detected
Murder 221 208 178 172 26 20
Murder(Gain) 20 16 11 9 1 1
Dacoity 51 45 44 36 5 1
Robbery 538 316 351 201 23 10
Chain Snatching 528 394 342 229 23 0
コード:親切に私は(もしあれば)これを達成するための別の方法
犯罪表を示唆
library(tables)
#CLASS 1 CRIMES 2014
c14 <- structure(list(`Reported` = c(221, 20, 51,
538, 528), `Detected` = c(208, 16, 45, 316, 394)), .Names = c("Reported",
"Detected"), row.names = c("Murder", "Murder(Gain)", "Dacoity", "Robbery", "Chain Snatching"), class = "data.frame")
c14
#CLASS 1 CRIMES 2015
c15 <- structure(list(`Reported` = c(178, 11, 44,
351, 342), `Detected` = c(172, 9,
36, 201, 229)), .Names = c("Reported",
"Detected"), row.names = c("Murder", "Murder(Gain)", "Dacoity",
"Robbery", "Chain Snatching"), class = "data.frame")
c15
#CLASS 1 CRIMES 31-01-2016
c16 <- structure(list(`Reported` = c(26, 1, 5,
23, 23), `Detected` = c(20, 1,
1, 10, 0)), .Names = c("Reported",
"Detected"), row.names = c("Murder", "Murder(Gain)", "Dacoity",
"Robbery", "Chain Snatching"), class = "data.frame")
c16
# rbind with rownames as a column
st <- rbind(
data.frame(c14, year = '2014', what = factor(rownames(c14), levels = rownames(c14)),
row.names= NULL, check.names = FALSE),
data.frame(c15,year = '2015',what = factor(rownames(c15), levels = rownames(c15)),
row.names = NULL,check.names = FALSE),
data.frame(c16,year = '2016',what = factor(rownames(c16), levels = rownames(c16)),
row.names = NULL,check.names = FALSE)
)
crimetable <- tabular(Heading()*what ~ year*(`Reported` +`Detected`)*Heading()*(identity),data=st)
crimetable
ありがとうございました –